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Allieeslabae

  • one year ago

12. What is the equation of the line perpendicular to the line y = x – 2 that passes through the point (4,3)? y = –4/9 x – 2 y = 9/4 x + 6 y = – 9/4 x + 12 y = – 9/4 x – 12

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  1. anonymous
    • one year ago
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    Hi

  2. Allieeslabae
    • one year ago
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    Hey do you know how to solve?

  3. anonymous
    • one year ago
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    add me as a fan so I can pm you then I will help you

  4. anonymous
    • one year ago
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    To find the the perpendicular line of y = x – 2, first we should start with the slope. The slope of the first equation is x. The slope of an equation perpendicular to the original will have the opposite reciprocal of the original slope. So we take the reciprical of x which is 1/x. The opposite (or negative) of 1/x would be -1/x. Make sense so far?

  5. Allieeslabae
    • one year ago
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    Okay so slope is x1 x1/ y1 y2 right?

  6. anonymous
    • one year ago
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    Could you explain where you got that answer from?

  7. Allieeslabae
    • one year ago
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    Thats how you find the slope right? Sorry I meant (x1, y1) and (x 2, y 2)

  8. anonymous
    • one year ago
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    That is how you would find the slope when given to pairs of coordinates. For example, if you were given the coordinates (3,4) and (1,2) \[\frac{ y2-y1 }{ x2-x1 } \rightarrow \frac{ 4-2 }{ 3-1 } \rightarrow \frac{ 2 }{ 2 } =1\] But to find the slope perpendicular to the original slope, you don't have to use the formula.

  9. Allieeslabae
    • one year ago
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    Okay im confused wht do i use then?

  10. anonymous
    • one year ago
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    It's just what I said earlier "the opposite reciprocal". That's it. :)

  11. Allieeslabae
    • one year ago
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    Okay thanks you. Ill try that!

  12. anonymous
    • one year ago
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    So you know how I got -1/x right?

  13. Allieeslabae
    • one year ago
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    nope, but I have to go to my tutor, Ill catch her up on what you told me! Thanks though!

  14. anonymous
    • one year ago
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    You're welcome. And good luck. :)

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