anonymous
  • anonymous
Please help........... Suppose we start with unlimited supplies of a 20% h2so4 solution and of a 50% h2so4 solution. We combine x liters of the first with y liters of the second to produce 7 liters of a 40% h2so4 solution. What does x equal?
Mathematics
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SOLVED
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chestercat
  • chestercat
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welshfella
  • welshfella
work in masses of pure sulphuric acid the mass of acid in 40% solution is 7 * 10 * 40 = 2800g
anonymous
  • anonymous
2.8?
welshfella
  • welshfella
x liters of 20% contains 200x g y liters of 50% = 500y g

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welshfella
  • welshfella
so 200x + 500y = 2800
anonymous
  • anonymous
yea
anonymous
  • anonymous
whats next
welshfella
  • welshfella
now we need to find y in terms of x. Note that the 50% solution i s 5/2 = 2.5 times as strong as the 20% So y liters of 50% = how many liters of 20%?
anonymous
  • anonymous
where did u get the 5/2?
welshfella
  • welshfella
the ratio of 50/20 = 2/2
welshfella
  • welshfella
* 5/2
anonymous
  • anonymous
oh okay
welshfella
  • welshfella
so y liters of 50% = 2.5x liters of 20%
anonymous
  • anonymous
yea
welshfella
  • welshfella
200x + 500*2.5x = 2800 solve for x
anonymous
  • anonymous
1.93?
welshfella
  • welshfella
yes
anonymous
  • anonymous
hmmmm it's supposed to be 2.33333333
welshfella
  • welshfella
oh yes I've gone wrong somewhere
welshfella
  • welshfella
something wrong in my logic somewhere
dumbcow
  • dumbcow
set up 2 equations... x + y = 7 20x + 50y = (40)(7)
welshfella
  • welshfella
yep thats the way
anonymous
  • anonymous
hmmm and then plug it in huh? y=7-x
dumbcow
  • dumbcow
yes
anonymous
  • anonymous
got it thanx
welshfella
  • welshfella
yea thats an easier way to do it. I still can't see what i did wrong . Worrying !
welshfella
  • welshfella
i see now!
welshfella
  • welshfella
200x + 500y = 2800 was correct then next step was to replace y with 7 - x
welshfella
  • welshfella
- that is y in tems of x.
welshfella
  • welshfella
I had a mental aberration!

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