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Compassionate

  • one year ago

What is happening here [ http://prntscr.com/8jajiq ]

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  1. anonymous
    • one year ago
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    Maths happening yo

  2. Compassionate
    • one year ago
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    Wouldn't it be \[120x - 3600 \space \space NOT \space \space 120x - 120 \times 30\]

  3. Compassionate
    • one year ago
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    Logic being: -120 * 30 - 3,600

  4. kropot72
    • one year ago
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    @Compassionate If you calculate the value of -120 * 30 when it arises, the final result of the calculation of the value of x does not change.

  5. Compassionate
    • one year ago
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    Come again? Put that in idiot terms for me.

  6. kropot72
    • one year ago
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    120x - 3600 = 80x 40x = 3600 x = 90

  7. kropot72
    • one year ago
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    @Compassionate Are you there?

  8. Compassionate
    • one year ago
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    \[120x - 3,600 = 80x \space \space \space, \space \space \space 40x = 3,600 \space \space \space , \space \space \space x = 90\]

  9. Compassionate
    • one year ago
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    Oh, I get it. So, we can solve it by multiplying out regularly, just the tutorial I am doing does it weird and shows the processes. That's what confused me. And since we know x - 30, we just say 90 - 30.

  10. Compassionate
    • one year ago
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    Can we do one more?

  11. kropot72
    • one year ago
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    Sure. Go ahead.

  12. Compassionate
    • one year ago
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    Train A has a speed 15 mi/hr greater than train B. If train A travels 150 miles in the same time train B travels 120 miles, what are the speeds of the two trains? Here is my logic. Train A = x + 15. \[\frac{ 150 }{ x +15} = \frac{120}{x}\]

  13. Compassionate
    • one year ago
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    150x = 120x + 1,800 30x = 1,800 x = 60 Recalling x + 15 for A's speed, 60 + 15 = 75

  14. kropot72
    • one year ago
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    All good.

  15. Compassionate
    • one year ago
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    Thanks a lot, man. I don't usually fan people, I only have a handful, maybe 9 -10, but I'll shoot you a fan because you're quite helpful.

  16. kropot72
    • one year ago
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    Thank you and you're welcome :)

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spraguer (Moderator)
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