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anonymous

  • one year ago

Find the product and simplify 4y/(y^2-81) × (y+9)/2y^2

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  1. anonymous
    • one year ago
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    2y3 y−9

  2. anonymous
    • one year ago
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    Thats not one of the options ):

  3. anonymous
    • one year ago
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    .....

  4. anonymous
    • one year ago
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    @Learner11

  5. anonymous
    • one year ago
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    2y3/y-9?

  6. anonymous
    • one year ago
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    Thats not one of the choices..

  7. anonymous
    • one year ago
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    sorry :(

  8. anonymous
    • one year ago
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    Thats ok.

  9. anonymous
    • one year ago
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    wait @ashley9337 . I think I can do it

  10. anonymous
    • one year ago
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    Okay thank you !!

  11. anonymous
    • one year ago
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    @imqwerty

  12. anonymous
    • one year ago
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    Can you tag me when you figure it out? Thank you

  13. anonymous
    • one year ago
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    oh! ok . sure :)

  14. anonymous
    • one year ago
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    @imqwerty

  15. anonymous
    • one year ago
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    @SyedMohammed98

  16. imqwerty
    • one year ago
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    \[\frac{ 2 }{ y(y-9) }\]

  17. anonymous
    • one year ago
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    Thank you so much!

  18. imqwerty
    • one year ago
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    np :)

  19. anonymous
    • one year ago
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    @imqwerty can you explain it to me ?

  20. imqwerty
    • one year ago
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    ok :)

  21. anonymous
    • one year ago
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    @imqwerty can you help me with 3 more problems?

  22. imqwerty
    • one year ago
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    \[\frac{ 4y }{ y^2-81 }\times \frac{ y+9 }{ 2y^2 }\] use the identity a^2 - b^2=(a+b)(a-b) in here - y^2 -81 u et-\[\frac{ 4y }{ (y+9)(y-9) }\times \frac{ y+9 }{2y^2}\]cut out the common things from numerator and denominator u get-\[\frac{ 2 }{ y(y-9) }\]

  23. imqwerty
    • one year ago
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    ok

  24. anonymous
    • one year ago
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    What is the least commonn denominator for 3/x and 2/4xy

  25. anonymous
    • one year ago
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    oh ! OK . Got it @imqwerty

  26. imqwerty
    • one year ago
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    least common divisor is the least common multiple. its 4xy

  27. anonymous
    • one year ago
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    Oh okay i understand. There a harder one that i have no idea about, find the lcd for x^2/(x^2+4x+3) and 2x/ (x^2+x-6)

  28. anonymous
    • one year ago
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    @imqwerty

  29. imqwerty
    • one year ago
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    x^2+4x+3 --->(x+3)(x+1) x^2+x-6------>(x+3)(x-2) so the lcd wuld be (x+3)(x-2)(x+1)

  30. anonymous
    • one year ago
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    Thank you for explaining it! okay can you help me with one last question

  31. imqwerty
    • one year ago
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    ok :)

  32. anonymous
    • one year ago
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    Find the quotient and show all work please so i can understand how to do it :) x^2-6x/7 ÷ x-6/x

  33. imqwerty
    • one year ago
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    ok :)

  34. imqwerty
    • one year ago
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    \[\frac{ x^2-6x }{ 7}\div \frac{ (x-6) }{ x}\] we know that \[a \div b =a \times \frac{ 1 }{ b }\] so we get - \[\frac{ x^2-6x }{ 7 } \times \frac{ x }{ (x-6) }\] take x common from x^2-6x u get->x(x-6) \[\frac{ x(x-6) }{ 7 } \times \frac{ x }{ x-6 }\]\[\frac{ x^2 }{ 7 }\]

  35. anonymous
    • one year ago
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    So the answer is x^2/7 right? Thank you so much for explaining it all.to me, i understand it now :)

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