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anonymous
 one year ago
How do extraneous solutions arise from radical equations?
anonymous
 one year ago
How do extraneous solutions arise from radical equations?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is pretty simple, say for example the problem is 7l2x+5l+3>5x8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02x+5>(5/7)x(11/7) and 2x+5>(5/7)x+(11/7) would be yours starting points for solving this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0an extraneous solution can only occur when there is a variable on both sides of the inequality sign, so one of the answers you'll get from this might not be a real solution to the problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(sry i forgot its 2x not 2x...)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so x>16/3 and x>5/3 (or something like that, for the second one) but since they both are greater than but its an and statement, the extraneous solution is x>5/3 since they both get to the right point, sry if that was complicated
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