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anonymous

  • one year ago

How do extraneous solutions arise from radical equations?

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  1. anonymous
    • one year ago
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    this is pretty simple, say for example the problem is 7l-2x+5l+3>5x-8

  2. anonymous
    • one year ago
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    -2x+5>(5/7)x-(11/7) and -2x+5>-(5/7)x+(11/7) would be yours starting points for solving this

  3. anonymous
    • one year ago
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    an extraneous solution can only occur when there is a variable on both sides of the inequality sign, so one of the answers you'll get from this might not be a real solution to the problem

  4. anonymous
    • one year ago
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    (sry i forgot its 2x not -2x...)

  5. anonymous
    • one year ago
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    so x>16/3 and x>5/3 (or something like that, for the second one) but since they both are greater than but its an and statement, the extraneous solution is x>5/3 since they both get to the right point, sry if that was complicated

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