anonymous
  • anonymous
How do extraneous solutions arise from radical equations?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
this is pretty simple, say for example the problem is 7l-2x+5l+3>5x-8
anonymous
  • anonymous
-2x+5>(5/7)x-(11/7) and -2x+5>-(5/7)x+(11/7) would be yours starting points for solving this
anonymous
  • anonymous
an extraneous solution can only occur when there is a variable on both sides of the inequality sign, so one of the answers you'll get from this might not be a real solution to the problem

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
(sry i forgot its 2x not -2x...)
anonymous
  • anonymous
so x>16/3 and x>5/3 (or something like that, for the second one) but since they both are greater than but its an and statement, the extraneous solution is x>5/3 since they both get to the right point, sry if that was complicated

Looking for something else?

Not the answer you are looking for? Search for more explanations.