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anonymous

  • one year ago

How do I use a table to find the solution to 5x+3=23, 8a-10=38, and 1/2x-5=-1?

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  1. anonymous
    • one year ago
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    make a X and Y column. Place an number you want under the x value and work out the problem. The resulting answer is your Y value.

  2. anonymous
    • one year ago
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    Let's start with a zero under the x. What is 5*0?

  3. anonymous
    • one year ago
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    X Y 0

  4. anonymous
    • one year ago
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    ? are you there?

  5. anonymous
    • one year ago
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    yes

  6. anonymous
    • one year ago
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    what is 5 times zero?

  7. anonymous
    • one year ago
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    0

  8. anonymous
    • one year ago
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    correct, so in your first problem it was 5*0+3 so what amount is left?

  9. anonymous
    • one year ago
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    3

  10. anonymous
    • one year ago
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    yes. So now you include that number in your table X Y 0 3

  11. anonymous
    • one year ago
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    How many numbers do you want you table to be?

  12. anonymous
    • one year ago
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    idk

  13. anonymous
    • one year ago
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    It doesn't matter i guess

  14. anonymous
    • one year ago
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    I guess we could do it up to 3

  15. anonymous
    • one year ago
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    Well, lets say 3 then. Pick a new number, say 1 place the 1 under the x column and multiply the 5 by one and then add 3

  16. anonymous
    • one year ago
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    you get 8

  17. anonymous
    • one year ago
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    yes, so place 8 under the Y value Show me what the new table looks like

  18. anonymous
    • one year ago
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    X Y 0 3 1 8

  19. anonymous
    • one year ago
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    good job. Now for our third number lets do -1 tell me what answer you get

  20. anonymous
    • one year ago
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    -2?

  21. anonymous
    • one year ago
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    good job. What does your finished table look like?

  22. anonymous
    • one year ago
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    X Y 0 3 1 8 -1 -2

  23. anonymous
    • one year ago
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    That is correct. You have successfully completed your first table. Now do the same for the others.

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