anonymous
  • anonymous
How do I use a table to find the solution to 5x+3=23, 8a-10=38, and 1/2x-5=-1?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
make a X and Y column. Place an number you want under the x value and work out the problem. The resulting answer is your Y value.
anonymous
  • anonymous
Let's start with a zero under the x. What is 5*0?
anonymous
  • anonymous
X Y 0

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anonymous
  • anonymous
? are you there?
anonymous
  • anonymous
yes
anonymous
  • anonymous
what is 5 times zero?
anonymous
  • anonymous
0
anonymous
  • anonymous
correct, so in your first problem it was 5*0+3 so what amount is left?
anonymous
  • anonymous
3
anonymous
  • anonymous
yes. So now you include that number in your table X Y 0 3
anonymous
  • anonymous
How many numbers do you want you table to be?
anonymous
  • anonymous
idk
anonymous
  • anonymous
It doesn't matter i guess
anonymous
  • anonymous
I guess we could do it up to 3
anonymous
  • anonymous
Well, lets say 3 then. Pick a new number, say 1 place the 1 under the x column and multiply the 5 by one and then add 3
anonymous
  • anonymous
you get 8
anonymous
  • anonymous
yes, so place 8 under the Y value Show me what the new table looks like
anonymous
  • anonymous
X Y 0 3 1 8
anonymous
  • anonymous
good job. Now for our third number lets do -1 tell me what answer you get
anonymous
  • anonymous
-2?
anonymous
  • anonymous
good job. What does your finished table look like?
anonymous
  • anonymous
X Y 0 3 1 8 -1 -2
anonymous
  • anonymous
That is correct. You have successfully completed your first table. Now do the same for the others.

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