calculusxy
  • calculusxy
help with exponents. question below.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
calculusxy
  • calculusxy
\[\large \frac{ (-u^3)^3 }{ u^{-2}v^4 \times -2v^0\times-2u^3v^4 }\]
calculusxy
  • calculusxy
@Nnesha @phi
Owlcoffee
  • Owlcoffee
Do you want to simplify it?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

calculusxy
  • calculusxy
yes
calculusxy
  • calculusxy
\[\frac{ u^9 }{ u^{-2}v^4\times-2v^0\times-2u^3v^4 }\]
Owlcoffee
  • Owlcoffee
Okay, in other words, the expression looks like this: \[\frac{ (-u^3)^3 }{ u ^{-2}v^4(-2v^0)(-2u^3v^4) }\]
calculusxy
  • calculusxy
i meant to put a -u^9
Owlcoffee
  • Owlcoffee
Let's begin by working with the denominator, let's associate all the "v"s and "u"s together sice this does work through the axiom of associative and commutative of multiplication: \[a.b=b.a\] \[a(c.b)=(a.c)b\] So, let's associate the denominator in order to make things clearer: \[\frac{ -u^9 }{ (-2)(u ^{-2})(u^3)(-2)(v^0)(v^4)(v^4) }\] That -2 x -2 can be represented as 4 so: \[\frac{ -u^9 }{ (4)(u ^{-2})(u^3)(v^0)(v^4)(v^4) }\] Now, let's make use of a useful property which has this form: \(a^ma^n=a^{m+n}\) This will allow us to operate those exponents: \[\frac{ -u^9 }{ (4)(u ^{(-2)+3})(v ^{0+4+4}) }\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.