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calculusxy
 one year ago
help with exponents.
question below.
calculusxy
 one year ago
help with exponents. question below.

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calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \frac{ (u^3)^3 }{ u^{2}v^4 \times 2v^0\times2u^3v^4 }\]

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0Do you want to simplify it?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ u^9 }{ u^{2}v^4\times2v^0\times2u^3v^4 }\]

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0Okay, in other words, the expression looks like this: \[\frac{ (u^3)^3 }{ u ^{2}v^4(2v^0)(2u^3v^4) }\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0i meant to put a u^9

Owlcoffee
 one year ago
Best ResponseYou've already chosen the best response.0Let's begin by working with the denominator, let's associate all the "v"s and "u"s together sice this does work through the axiom of associative and commutative of multiplication: \[a.b=b.a\] \[a(c.b)=(a.c)b\] So, let's associate the denominator in order to make things clearer: \[\frac{ u^9 }{ (2)(u ^{2})(u^3)(2)(v^0)(v^4)(v^4) }\] That 2 x 2 can be represented as 4 so: \[\frac{ u^9 }{ (4)(u ^{2})(u^3)(v^0)(v^4)(v^4) }\] Now, let's make use of a useful property which has this form: \(a^ma^n=a^{m+n}\) This will allow us to operate those exponents: \[\frac{ u^9 }{ (4)(u ^{(2)+3})(v ^{0+4+4}) }\]
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