A bullet is fired into the air with an initial velocity of 1,300 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 5 seconds?
Can someone tell me what formula I should me using? I think I can do it myself but I can't remember velocity.
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horizontal component of the velocity = 1300 cos 45

equate this to d/5 to find d

So it would be 919.23 ?

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