anonymous
  • anonymous
A bullet is fired into the air with an initial velocity of 1,300 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 5 seconds? Can someone tell me what formula I should me using? I think I can do it myself but I can't remember velocity. Medals for everyone :)
Mathematics
schrodinger
  • schrodinger
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welshfella
  • welshfella
horizontal component of the velocity = 1300 cos 45
welshfella
  • welshfella
equate this to d/5 to find d
anonymous
  • anonymous
So it would be 919.23 ?

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anonymous
  • anonymous
Sorry I mean 183.84
welshfella
  • welshfella
that would be the horizontal velocity yes
welshfella
  • welshfella
919.23 = d / 5 find d
anonymous
  • anonymous
4596.15?
anonymous
  • anonymous
Thank you
welshfella
  • welshfella
looks good
welshfella
  • welshfella
yw
anonymous
  • anonymous
I got these out as I;m doing physics work right now too so thought I'd leave these here: \[V=V_0 + at\]\[X=1/2 (V_0+V)t\]\[X=V_0T+1/2(AT^2)\]\[V^2=V_0^2+2ax\]
welshfella
  • welshfella
the horizontal component of the velocity is constant as gravity has no effect on it
welshfella
  • welshfella
yes these are the equations for constant acceleration
welshfella
  • welshfella
- useful amongst other things, for solving problems of projectiles moving under the infuence of gravity

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