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anonymous
 one year ago
A bullet is fired into the air with an initial velocity of 1,300 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 5 seconds?
Can someone tell me what formula I should me using? I think I can do it myself but I can't remember velocity.
Medals for everyone :)
anonymous
 one year ago
A bullet is fired into the air with an initial velocity of 1,300 feet per second at an angle for 45° from the horizontal. What is the horizontal distance traveled by the bullet in 5 seconds? Can someone tell me what formula I should me using? I think I can do it myself but I can't remember velocity. Medals for everyone :)

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.2horizontal component of the velocity = 1300 cos 45

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2equate this to d/5 to find d

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would be 919.23 ?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2that would be the horizontal velocity yes

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2919.23 = d / 5 find d

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got these out as I;m doing physics work right now too so thought I'd leave these here: \[V=V_0 + at\]\[X=1/2 (V_0+V)t\]\[X=V_0T+1/2(AT^2)\]\[V^2=V_0^2+2ax\]

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the horizontal component of the velocity is constant as gravity has no effect on it

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes these are the equations for constant acceleration

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2 useful amongst other things, for solving problems of projectiles moving under the infuence of gravity
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