## anonymous one year ago Need help with calculus question quickly!

1. anonymous

2. zepdrix

$\large\rm |x-3|=\cases{(x-3),\qquad x\ge3\\ \rm -(x-3),\quad x\lt3}$

3. zepdrix

So when we're on the left side of 3, Our |x-3| is -(x-3), giving us a function of:$\large\rm t(x)=2^x-\frac{-(x-3)}{(x-3)}$Err I guess it would be better to do this with limits. Approach 3 from the left, and seperately approach 3 from the right and see if the two pieces connect. If they don't, we have a jump discontinuity.

4. zepdrix

$\large\rm \lim_{x\to3^-}t(x)=2^{x}-\frac{-(x-3)}{(x-3)}$Do a cancellation before plugging the 3 in :)

5. anonymous

Thanks! @zepdrix

6. zepdrix

Did you figure out out Princess Jasmine? :o

7. anonymous

Yes. I said it was a jump discontinuity. I just needed a starting point.

8. anonymous

@zepdrix