Spring98
  • Spring98
Part A: If (2^6)^x = 1, what is the value of x? Explain your answer. Part B: If (5^0)^x = 1, what are the possible values of x? Explain your answer.
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Spring98
  • Spring98
@jdoe0001 Can you help me with this one too. I can't pas my quiz and if i don't get 80% or more i can't go on.
jdoe0001
  • jdoe0001
\(\bf \textit{part A, multiply both sides by }\qquad \cfrac{1}{26} \\ \quad \\ \textit{part B, multiply both sides by }\qquad \cfrac{1}{50}\) what does that give you?
Spring98
  • Spring98
they both equal 1 @jdoe0001

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Spring98
  • Spring98
is that right?
jdoe0001
  • jdoe0001
\(\bf (26)x=1\implies \cfrac{1}{\cancel{26}}\cdot (\cancel{26})x=1\cdot \cfrac{1}{26}\implies x=? \\ \quad \\ \quad \\ (50)x=1\implies \cfrac{1}{\cancel{50}}\cdot (\cancel{50})x=1\cdot \cfrac{1}{50}\implies x=?\)
Spring98
  • Spring98
0.0384615384615385 is part A and 0.02for part B @jdoe0001
jdoe0001
  • jdoe0001
\(\huge \circ.\circ\)
jdoe0001
  • jdoe0001
notice, the number on the left cancelled out with the denominator
Spring98
  • Spring98
but what happened with the exponents?
Spring98
  • Spring98
Spring98
  • Spring98
@zepdrix @jdoe0001 can you guys plz help me?
jdoe0001
  • jdoe0001
woops, got a typo there \(\bf (26)x=1\implies \cfrac{1}{\cancel{26}}\cdot (\cancel{26})x=1\cdot \cfrac{1}{26}\implies \cfrac{1}{1}\cdot x=\cfrac{1}{26}\implies x=\cfrac{1}{26} \\ \quad \\ \quad \\ (50)x=1\implies \cfrac{1}{\cancel{50}}\cdot (\cancel{50})x=1\cdot \cfrac{1}{50}\implies \cfrac{1}{1}\cdot x=\cfrac{1}{50}\implies x=\cfrac{1}{50}\)
Spring98
  • Spring98
i know but there is expopnents and i'm going to get this wrong.
jdoe0001
  • jdoe0001
ohh...shoot.. is not what you originally posted though hmm.... need to dash in secs..... you may want to repost
zepdrix
  • zepdrix
\[\large\rm (2^{6})^x=1\]Applying a rule of exponents to the left side gives us\[\large\rm 2^{6x}=1\]Rewrite the right side as a power of 2. 2 to what power = 1?
Spring98
  • Spring98
ok i will repost and i will tag you k @jdoe0001
Spring98
  • Spring98
Is it 0? @zepdrix
zepdrix
  • zepdrix
Good. Anything to the zero power is 1. 2^0=1. Therefore we can write our equation:\[\large\rm 2^{6x}=1\]as\[\large\rm 2^{6x}=2^0\]Since the bases are the same, we can equate the exponents.
Spring98
  • Spring98
how did the 2 end up a 0. and isn't the x supposed to be a 0
Spring98
  • Spring98
zepdrix
  • zepdrix
I didn't change anything about the left side. I rewrite 1 as 2^0.
zepdrix
  • zepdrix
Therefore, equating the exponents gives us \(\large\rm 6x=0\) which leads to \(\large\rm x=0\)
zepdrix
  • zepdrix
For the other problem:\[\large\rm (5^0)^x = \color{orangered}{1}\]again, rewrite 1 as a power of 5,\[\large\rm (5^0)^x = \color{orangered}{5^0}\]Apply exponent rule to the left side,\[\large\rm (5^{0x}) = \color{orangered}{5^0}\]Which leads to\[\large\rm 0x=0\]And it looks like ANY value of x is going to solve this one.

Looking for something else?

Not the answer you are looking for? Search for more explanations.