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shreenithaa

  • one year ago

write the solution in interval notation using the union sign U 2y+5<5y-1 or 5y-1<3y-7

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  1. shreenithaa
    • one year ago
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    @ganeshie8 @zepdrix

  2. zepdrix
    • one year ago
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    \[\large\rm 2y+5\lt 5y-1\]What do you get when you simplify? :)

  3. shreenithaa
    • one year ago
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    2y+5<5y-1 or 5y-1<3y-7 -5 -5 +1 +1 2y<5y-6 or 5y<3y-6 -5y -5y -3y -3y -3y<6 or 2y<-8 //////////////// -3 2 y>-2 or y<-4

  4. shreenithaa
    • one year ago
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    @zepdrix

  5. shreenithaa
    • one year ago
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    how do u write the interval notation using the union sign

  6. zepdrix
    • one year ago
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    Hmm, those don't look quite right. Here is what I would recomment for the first relationship.\[\large\rm 2y+5\lt 5y-1\]Subtracting 2y from each side,\[\large\rm 5\lt 3y-1\]Adding 1,\[\large\rm 6\lt 3y\]Divide 3 gives us,\[\large\rm 2\lt y\]

  7. shreenithaa
    • one year ago
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    how do u do the union sign?

  8. zepdrix
    • one year ago
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    Again, to do it in text, you'll have to google it :) lol In the equation tool, it's the command \cup

  9. shreenithaa
    • one year ago
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    no i mean write it in interval notation

  10. zepdrix
    • one year ago
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    Well we're not quite there yet :O Both of your y values look incorrect. The other y interval I think is \(\large\rm y\lt -3\) That's what I'm coming up with at least, hmm

  11. shreenithaa
    • one year ago
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    i checked and i got t right

  12. zepdrix
    • one year ago
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    ...?? 0_o -2 and -4 are not the correct values though..

  13. shreenithaa
    • one year ago
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    yeah -2 isnt \ just checked forgot it was -6

  14. shreenithaa
    • one year ago
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    -4 is right though

  15. zepdrix
    • one year ago
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    No, neither number is correct :( One sec..

  16. zepdrix
    • one year ago
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    Ya in the first one, it was supposed to be -6, not 6. So that should change it to \(\large\rm y\gt 2\) In the second one, your -6 turned into a -8 halfway through. So fixing that should give you \(\large\rm y\lt -3\)

  17. shreenithaa
    • one year ago
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    yeah nevermind

  18. zepdrix
    • one year ago
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    Hard to keep track of all these little steps :D lol

  19. shreenithaa
    • one year ago
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    i c my mistake sorry

  20. shreenithaa
    • one year ago
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    now finally how do u do the union thingy

  21. zepdrix
    • one year ago
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    \(\large\rm y\lt-3 ~OR~ y\gt2\) The word OR means union, as you said :)\[\large\rm y\lt-3 ~\cup~ y\gt2\]Let's write the y<3 as an interval.

  22. zepdrix
    • one year ago
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    y<-3*

  23. shreenithaa
    • one year ago
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    so the u is replaced for or?

  24. zepdrix
    • one year ago
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    Yes :) The union symbol and the word OR mean the same thing

  25. zepdrix
    • one year ago
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    But we have a little more to do

  26. shreenithaa
    • one year ago
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    ooh wow does that sound easy now what grade r u in and state

  27. shreenithaa
    • one year ago
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    i only need the union sign

  28. zepdrix
    • one year ago
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    \(\large\rm y\lt-3\) can be written as \(\Large\rm \left(-\infty,-3\right)\) -3 is the largest value this interval can have. and every number below that should be included in the interval. Does that make sense? :o

  29. zepdrix
    • one year ago
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    oh you don't need the intervals? :D

  30. shreenithaa
    • one year ago
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    nope the intervals have to be as the union sign or something like that

  31. shreenithaa
    • one year ago
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    these are disjunctions so yeah

  32. shreenithaa
    • one year ago
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    lol

  33. zepdrix
    • one year ago
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    If we're using the Union symbol, we usually write the inequalities as intervals. So for our problem,\[\large\rm y\lt-3 ~OR~ y\gt2\]We would write it as\[\large\rm (-\infty,-3)\cup(2,\infty)\]

  34. shreenithaa
    • one year ago
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    thnx what grade r u in

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