• anonymous
I have a calculus problem: cubed root of (x^3+6x+1) times x^7 I have worked out part of this problem but there is a part which I will identify that I am unsure of how the solution is arrived at. Let F(x)=f(x)*g(x) Let f(x)= (x³+6x+1)^(1/3) d/dx (x³+6x+1)^(1/3)= (x²+2)/(x³+6x+1)^(2/3) Let g(x)=x^7 d/dx x^7= 7x^6 F'(x)= (x³+6x+1)^(1/3)*7x^6 +x^7 * (x²+2)/(x³+6x+1)^(2/3) read next
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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