I have a calculus problem:
cubed root of (x^3+6x+1) times x^7
I have worked out part of this problem but there is a part which I will identify that I am unsure of how the solution is arrived at.
Let F(x)=f(x)*g(x)
Let f(x)= (x³+6x+1)^(1/3)
d/dx (x³+6x+1)^(1/3)= (x²+2)/(x³+6x+1)^(2/3)
Let g(x)=x^7
d/dx x^7= 7x^6
F'(x)= (x³+6x+1)^(1/3)*7x^6 +x^7 * (x²+2)/(x³+6x+1)^(2/3)
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