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YumYum247

  • one year ago

LuLu!!! :D

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  1. inkyvoyd
    • one year ago
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    what work (no pun intended) have you done so far?

  2. YumYum247
    • one year ago
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    the work of writing out the question....no pun intended!! :D

  3. inkyvoyd
    • one year ago
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    well go make some progress. at least draw a fbd

  4. YumYum247
    • one year ago
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    nnah i was joking.... i've done some of the questions but they are tooo long and difficult to type it here....

  5. YumYum247
    • one year ago
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    for the first question this is what i did...

  6. YumYum247
    • one year ago
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    first i figured out the normal force the earth was exerting the block of wood. Normal force = mass x gravity normal force = 0.72Kg X 9.80m/sec^2 Normal force = 7.05N This is my normal force.

  7. inkyvoyd
    • one year ago
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    looks good

  8. YumYum247
    • one year ago
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    from here i used te frictional formula to get my force of friction. Force of friction = μk x 7.05N Force of friction = 4.51N i got my friction.

  9. YumYum247
    • one year ago
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    Nor that i ad my frictinal force and normal force. i plugged them into te formula to get my net force Applied force - frictional force = m x change in velocity/time Applied force - 4.51N = 0.72Kg x 0.8m/sec^2 Applied force = 4.51N + 0.57N Applied force = 5.08N HEre is te answer to my first question....

  10. YumYum247
    • one year ago
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    now have absolutely no clue as to what do i need to do for te next question -_-

  11. inkyvoyd
    • one year ago
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    applied force is C.

  12. inkyvoyd
    • one year ago
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    you actually already finished the question lol

  13. YumYum247
    • one year ago
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    what chu mean o_o

  14. YumYum247
    • one year ago
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    can i use the force of friction for te second question???????????

  15. inkyvoyd
    • one year ago
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    applied force - frictional force = net force

  16. YumYum247
    • one year ago
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    i got that but help me here for a sec, can i use the frictional force tat i got for the second question

  17. inkyvoyd
    • one year ago
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    yes. that's why i said you did the problem already

  18. YumYum247
    • one year ago
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    aaitt....:D

  19. YumYum247
    • one year ago
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    now last thing...

  20. YumYum247
    • one year ago
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    how do i do the last question?!?!?!?!

  21. inkyvoyd
    • one year ago
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    silly. you started out by doing the last question.

  22. inkyvoyd
    • one year ago
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    applied force= actual force.

  23. YumYum247
    • one year ago
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    what chu mean?!?!?!?

  24. inkyvoyd
    • one year ago
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    Applied force - frictional force = m x change in velocity/time Applied force - 4.51N = 0.72Kg x 0.8m/sec^2 Applied force = 4.51N + 0.57N Applied force = 5.08N =>applied force is the actual force frictional force is the answer to part b m x change in velocity/time is net force

  25. YumYum247
    • one year ago
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    so my applied force is te actual force....O_O

  26. YumYum247
    • one year ago
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    LOL i didn't know i am so genius :D Thanks LOve

  27. inkyvoyd
    • one year ago
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    yeh.. net force is the sum of all forces.

  28. YumYum247
    • one year ago
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    aigt...i need to go to the washroom.............................:"D

  29. YumYum247
    • one year ago
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    @so before you go, the frictional force = 4.51N right? and the actual applied force = 5.08N The net force would be 5.08N - 4.51N = 0.57N right?!?!?!

  30. YumYum247
    • one year ago
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    @inkyvoyd please come back :(

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