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what work (no pun intended) have you done so far?
the work of writing out the question....no pun intended!! :D
well go make some progress. at least draw a fbd
nnah i was joking.... i've done some of the questions but they are tooo long and difficult to type it here....
for the first question this is what i did...
first i figured out the normal force the earth was exerting the block of wood. Normal force = mass x gravity normal force = 0.72Kg X 9.80m/sec^2 Normal force = 7.05N This is my normal force.
from here i used te frictional formula to get my force of friction. Force of friction = μk x 7.05N Force of friction = 4.51N i got my friction.
Nor that i ad my frictinal force and normal force. i plugged them into te formula to get my net force Applied force - frictional force = m x change in velocity/time Applied force - 4.51N = 0.72Kg x 0.8m/sec^2 Applied force = 4.51N + 0.57N Applied force = 5.08N HEre is te answer to my first question....
now have absolutely no clue as to what do i need to do for te next question -_-
applied force is C.
you actually already finished the question lol
what chu mean o_o
can i use the force of friction for te second question???????????
applied force - frictional force = net force
i got that but help me here for a sec, can i use the frictional force tat i got for the second question
yes. that's why i said you did the problem already
now last thing...
how do i do the last question?!?!?!?!
silly. you started out by doing the last question.
applied force= actual force.
what chu mean?!?!?!?
Applied force - frictional force = m x change in velocity/time Applied force - 4.51N = 0.72Kg x 0.8m/sec^2 Applied force = 4.51N + 0.57N Applied force = 5.08N =>applied force is the actual force frictional force is the answer to part b m x change in velocity/time is net force
so my applied force is te actual force....O_O
LOL i didn't know i am so genius :D Thanks LOve
yeh.. net force is the sum of all forces.
aigt...i need to go to the washroom.............................:"D
@so before you go, the frictional force = 4.51N right? and the actual applied force = 5.08N The net force would be 5.08N - 4.51N = 0.57N right?!?!?!
@inkyvoyd please come back :(