LuLu!!! :D

- YumYum247

LuLu!!! :D

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- katieb

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- inkyvoyd

what work (no pun intended) have you done so far?

- YumYum247

the work of writing out the question....no pun intended!! :D

- inkyvoyd

well go make some progress. at least draw a fbd

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## More answers

- YumYum247

nnah i was joking.... i've done some of the questions but they are tooo long and difficult to type it here....

- YumYum247

for the first question this is what i did...

- YumYum247

first i figured out the normal force the earth was exerting the block of wood.
Normal force = mass x gravity
normal force = 0.72Kg X 9.80m/sec^2
Normal force = 7.05N This is my normal force.

- inkyvoyd

looks good

- YumYum247

from here i used te frictional formula to get my force of friction.
Force of friction = μk x 7.05N
Force of friction = 4.51N i got my friction.

- YumYum247

Nor that i ad my frictinal force and normal force. i plugged them into te formula to get my net force
Applied force - frictional force = m x change in velocity/time
Applied force - 4.51N = 0.72Kg x 0.8m/sec^2
Applied force = 4.51N + 0.57N
Applied force = 5.08N
HEre is te answer to my first question....

- YumYum247

now have absolutely no clue as to what do i need to do for te next question -_-

- inkyvoyd

applied force is C.

- inkyvoyd

you actually already finished the question lol

- YumYum247

what chu mean o_o

- YumYum247

can i use the force of friction for te second question???????????

- inkyvoyd

applied force - frictional force = net force

- YumYum247

i got that but help me here for a sec, can i use the frictional force tat i got for the second question

- inkyvoyd

yes. that's why i said you did the problem already

- YumYum247

aaitt....:D

- YumYum247

now last thing...

- YumYum247

how do i do the last question?!?!?!?!

- inkyvoyd

silly. you started out by doing the last question.

- inkyvoyd

applied force= actual force.

- YumYum247

what chu mean?!?!?!?

- inkyvoyd

Applied force - frictional force = m x change in velocity/time
Applied force - 4.51N = 0.72Kg x 0.8m/sec^2
Applied force = 4.51N + 0.57N
Applied force = 5.08N
=>applied force is the actual force
frictional force is the answer to part b
m x change in velocity/time is net force

- YumYum247

so my applied force is te actual force....O_O

- YumYum247

LOL i didn't know i am so genius :D Thanks LOve

- inkyvoyd

yeh.. net force is the sum of all forces.

- YumYum247

aigt...i need to go to the washroom.............................:"D

- YumYum247

@so before you go, the frictional force = 4.51N right? and the actual applied force = 5.08N
The net force would be 5.08N - 4.51N = 0.57N right?!?!?!

- YumYum247

@inkyvoyd please come back :(

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