## geekfromthefutur one year ago Need help plz been stuck on this for awhile cant find anything to help give medal and fan

1. geekfromthefutur

2. just_gymnast_me

3. geekfromthefutur

ok

4. geekfromthefutur

Find the square of each imaginary number. 1.-3i 2.$i \sqrt{3}$ 3.$2i \sqrt{5}$

5. geekfromthefutur

|dw:1442971089070:dw|

6. anonymous

This is the basic fact you need to start with: $i=\sqrt{-1}$ From there we get $i^2=-1$

7. anonymous

1. (-3i)² = (-3)²(i)² = 9(-1) = -9 make sense?

8. geekfromthefutur

Oh ok cuz the 2 is saying 3 x 3=9

9. anonymous

right

10. geekfromthefutur

Ok so lets c if i can get the 2nd one and u check it if u want

11. anonymous

ok

12. geekfromthefutur

Wouldt it be the same since its 3 as well but negitive

13. anonymous

right it's -3

14. geekfromthefutur

Sweet

15. geekfromthefutur

ok so 3 would be like 5x5 since theres a 2 or it would be that and 2x2 because they all have the exponent of 2

16. anonymous

they would all have the exponent

17. geekfromthefutur

ok so it will be 5x5 and 2x2

18. anonymous

√5 * √5 and 2*2

19. geekfromthefutur

what does that sign mean againt not the * sign but doesn't that mean divide

20. geekfromthefutur

*again

21. anonymous

that's the square root sign. it basically cancels the exponent

22. geekfromthefutur

oh ok

23. anonymous

|dw:1442971897707:dw|

24. geekfromthefutur

ok so -20

25. anonymous

yep

26. geekfromthefutur

alrighty the 4th one seems a little confusing

27. geekfromthefutur

|dw:1442972072833:dw| ??

28. anonymous

it's the same deal. the square root just cancels the exponent and leaves the number|dw:1442972135034:dw|

29. geekfromthefutur

oh ok

30. geekfromthefutur

Ty for your help i really needed this

31. anonymous

sure no problem

32. anonymous

you got the last one?

33. geekfromthefutur

Yea i can just copy the last one its just change in didgets and same format lookin

34. geekfromthefutur

digits

35. anonymous

true