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anonymous
 one year ago
The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 42 and the common ratio is three fourths. Write the sum in sigma notation and calculate the sum that will be the upper limit of this population.
anonymous
 one year ago
The population of a local species of dragonfly can be found using an infinite geometric series where a1 = 42 and the common ratio is three fourths. Write the sum in sigma notation and calculate the sum that will be the upper limit of this population.

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what do you have so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i havedw:1442973187600:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you're very close

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh and the 42(3/4)^i1?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it should be \[\Large \sum_{i=1}^{\infty} 42\left(\frac{3}{4}\right)^{i1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes! That's what I meant. Thankyou :)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1now `calculate the sum that will be the upper limit of this population.`

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmmm...it wouldn't be diveregent right?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you see how a = 42 and r = 3/4 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! So we are plugging it into the geometric series formula!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah since r < 1 is true, we can use S = a/(1r)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me on another?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the sum of the arithmetic sequence 8, 14, 20 …, if there are 24 terms?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1first term = ?? common difference = ??

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1C.D is +6 actually

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1we add 6 to each term to get the next one

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1now use the formula \[\Large S_n = \frac{n(2a+d(n1))}{2}\] n = number of terms added up a = first term d = common difference

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So far, I have s24=24(16+6n1/2)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1n = 24, so replace the n in n1 with 24

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large S_n = \frac{n(2a+d(n1))}{2}\] \[\Large S_{24} = \frac{24(2*8+6(241))}{2}\] \[\Large S_{24} = ???\]
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