## geekfromthefutur one year ago Plz help with these questions to see if im right

1. geekfromthefutur

we have to determine if the equation has real or imaginary solutions by solving

2. geekfromthefutur

3. geekfromthefutur

4. geekfromthefutur

@jim_thompson5910 @surjithayer

5. jim_thompson5910

show what you have so far

6. geekfromthefutur

Well i only have the first one and i said it was a real soultions

7. jim_thompson5910

yes that first one definitely has 2 real solutions. Were you able to find the actual solutions?

8. TheCatMan

with the 3rd equation start by subtracting 9 to get (x^2=-6)

9. geekfromthefutur

yea well i didi have it written down

10. jim_thompson5910

11. TheCatMan

the soluion would come out to a decimal if you work the rest out thats your hint for question 3

12. geekfromthefutur

x= ± 2 21−−√ 7 x≈1.30930734,−1.30930734

13. geekfromthefutur

thats all i havee for number 1

14. geekfromthefutur

for number two i have this hold on

15. geekfromthefutur

x=±i6√

16. TheCatMan

i say spot one because of the simplification it checks out

17. geekfromthefutur

so i think number two is imaginary soutions bevause of the i in the answer

18. jim_thompson5910

#2 does have imaginary (aka non real) solutions but it's not x=±i6√

19. geekfromthefutur

What is it

20. TheCatMan

then again i am shorting out from the day i had at school with 3 tests so im good for a few helpings tonight

21. jim_thompson5910

after you distributed, what did you get?

22. geekfromthefutur

i just put it in a math solver

23. geekfromthefutur

24. TheCatMan

0 doennt equal -3

25. jim_thompson5910

oh, so you're working on #3 then

26. geekfromthefutur

nope still 2nd

27. TheCatMan

im worked out the second one and got 0=-3 and thats not possible

28. jim_thompson5910

i'm referring to this one as the second (since you posted it second) http://assets.openstudy.com/updates/attachments/56020960e4b0ad22e8a696f9-geekfromthefutur-1442974199899-win_20150922_220854.jpg

29. geekfromthefutur

Ohhh sorry my bad yea we are working on the 3rd one my bad

30. TheCatMan

square root 6

31. geekfromthefutur

How would i write this in two little lines catman

32. TheCatMan

sorry my pc just crashed but it restarts fast

33. geekfromthefutur

ok

34. TheCatMan

you round the decimal to the nearest hundreth

35. TheCatMan

so it would be 2.45 instead of 2.449

36. geekfromthefutur

ok

37. geekfromthefutur

Wait what decimal

38. TheCatMan

the square root of 6

39. TheCatMan

is not a whole number

40. geekfromthefutur

2.44948974278

41. TheCatMan

but instead it would be 2.45 as you round the 9 to the 2.44 to a 2.45. note you cannot round up a if the number behind it is less than five for example if the number was 32 it cannot be rounded to 40 it would round down to 30

42. geekfromthefutur

ok and what about the next problem

43. jim_thompson5910

you mean #3?

44. geekfromthefutur

yea

45. jim_thompson5910

if you subtract 9 from both sides, you'd get x^2 = -6 taking the square root of both sides leads to what your solver got

46. geekfromthefutur

ok x=i,−i

47. geekfromthefutur

so imaginary

48. jim_thompson5910

no it should be $\Large x = \pm i*\sqrt{6}$

49. geekfromthefutur

oh ok

50. geekfromthefutur

Real quick @jim_thompson5910 this went for this one?

51. jim_thompson5910

oh, I see now yes, the solution to that one is definitely x = i or x = -i

52. geekfromthefutur

So what we went over was for this one

53. geekfromthefutur

but the one you said it should be that was for the middle one

54. jim_thompson5910

yeah the solution to #2 is x = i or x = -i