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we have to determine if the equation has real or imaginary solutions by solving

show what you have so far

Well i only have the first one and i said it was a real soultions

yes that first one definitely has 2 real solutions. Were you able to find the actual solutions?

with the 3rd equation start by subtracting 9 to get (x^2=-6)

yea well i didi have it written down

ok show us your work please

the soluion would come out to a decimal if you work the rest out thats your hint for question 3

x= ± 2 21−−√ 7
x≈1.30930734,−1.30930734

thats all i havee for number 1

for number two i have this hold on

x=±i6√

i say spot one because of the simplification it checks out

so i think number two is imaginary soutions bevause of the i in the answer

#2 does have imaginary (aka non real) solutions
but it's not x=±i6√

What is it

after you distributed, what did you get?

i just put it in a math solver

0 doennt equal -3

oh, so you're working on #3 then

nope still 2nd

im worked out the second one and got 0=-3 and thats not possible

Ohhh sorry my bad yea we are working on the 3rd one my bad

square root 6

How would i write this in two little lines catman

sorry my pc just crashed but it restarts fast

you round the decimal to the nearest hundreth

so it would be 2.45 instead of 2.449

Wait what decimal

the square root of 6

is not a whole number

2.44948974278

ok and what about the next problem

you mean #3?

yea

ok x=i,−i

so imaginary

no it should be \[\Large x = \pm i*\sqrt{6}\]

oh ok

Real quick @jim_thompson5910 this went for this one?

oh, I see now
yes, the solution to that one is definitely x = i or x = -i

So what we went over was for this one

but the one you said it should be that was for the middle one

yeah the solution to #2 is x = i or x = -i