geekfromthefutur
  • geekfromthefutur
Plz help with these questions to see if im right
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
geekfromthefutur
  • geekfromthefutur
we have to determine if the equation has real or imaginary solutions by solving
geekfromthefutur
  • geekfromthefutur
geekfromthefutur
  • geekfromthefutur

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geekfromthefutur
  • geekfromthefutur
@jim_thompson5910 @surjithayer
jim_thompson5910
  • jim_thompson5910
show what you have so far
geekfromthefutur
  • geekfromthefutur
Well i only have the first one and i said it was a real soultions
jim_thompson5910
  • jim_thompson5910
yes that first one definitely has 2 real solutions. Were you able to find the actual solutions?
TheCatMan
  • TheCatMan
with the 3rd equation start by subtracting 9 to get (x^2=-6)
geekfromthefutur
  • geekfromthefutur
yea well i didi have it written down
jim_thompson5910
  • jim_thompson5910
ok show us your work please
TheCatMan
  • TheCatMan
the soluion would come out to a decimal if you work the rest out thats your hint for question 3
geekfromthefutur
  • geekfromthefutur
x= ± 2 21−−√ 7 x≈1.30930734,−1.30930734
geekfromthefutur
  • geekfromthefutur
thats all i havee for number 1
geekfromthefutur
  • geekfromthefutur
for number two i have this hold on
geekfromthefutur
  • geekfromthefutur
x=±i6√
TheCatMan
  • TheCatMan
i say spot one because of the simplification it checks out
geekfromthefutur
  • geekfromthefutur
so i think number two is imaginary soutions bevause of the i in the answer
jim_thompson5910
  • jim_thompson5910
#2 does have imaginary (aka non real) solutions but it's not x=±i6√
geekfromthefutur
  • geekfromthefutur
What is it
TheCatMan
  • TheCatMan
then again i am shorting out from the day i had at school with 3 tests so im good for a few helpings tonight
jim_thompson5910
  • jim_thompson5910
after you distributed, what did you get?
geekfromthefutur
  • geekfromthefutur
i just put it in a math solver
geekfromthefutur
  • geekfromthefutur
1 Attachment
TheCatMan
  • TheCatMan
0 doennt equal -3
jim_thompson5910
  • jim_thompson5910
oh, so you're working on #3 then
geekfromthefutur
  • geekfromthefutur
nope still 2nd
TheCatMan
  • TheCatMan
im worked out the second one and got 0=-3 and thats not possible
jim_thompson5910
  • jim_thompson5910
i'm referring to this one as the second (since you posted it second) http://assets.openstudy.com/updates/attachments/56020960e4b0ad22e8a696f9-geekfromthefutur-1442974199899-win_20150922_220854.jpg
geekfromthefutur
  • geekfromthefutur
Ohhh sorry my bad yea we are working on the 3rd one my bad
TheCatMan
  • TheCatMan
square root 6
geekfromthefutur
  • geekfromthefutur
How would i write this in two little lines catman
TheCatMan
  • TheCatMan
sorry my pc just crashed but it restarts fast
geekfromthefutur
  • geekfromthefutur
ok
TheCatMan
  • TheCatMan
you round the decimal to the nearest hundreth
TheCatMan
  • TheCatMan
so it would be 2.45 instead of 2.449
geekfromthefutur
  • geekfromthefutur
ok
geekfromthefutur
  • geekfromthefutur
Wait what decimal
TheCatMan
  • TheCatMan
the square root of 6
TheCatMan
  • TheCatMan
is not a whole number
geekfromthefutur
  • geekfromthefutur
2.44948974278
TheCatMan
  • TheCatMan
but instead it would be 2.45 as you round the 9 to the 2.44 to a 2.45. note you cannot round up a if the number behind it is less than five for example if the number was 32 it cannot be rounded to 40 it would round down to 30
geekfromthefutur
  • geekfromthefutur
ok and what about the next problem
jim_thompson5910
  • jim_thompson5910
you mean #3?
geekfromthefutur
  • geekfromthefutur
yea
jim_thompson5910
  • jim_thompson5910
if you subtract 9 from both sides, you'd get x^2 = -6 taking the square root of both sides leads to what your solver got
geekfromthefutur
  • geekfromthefutur
ok x=i,−i
geekfromthefutur
  • geekfromthefutur
so imaginary
jim_thompson5910
  • jim_thompson5910
no it should be \[\Large x = \pm i*\sqrt{6}\]
geekfromthefutur
  • geekfromthefutur
oh ok
geekfromthefutur
  • geekfromthefutur
Real quick @jim_thompson5910 this went for this one?
jim_thompson5910
  • jim_thompson5910
oh, I see now yes, the solution to that one is definitely x = i or x = -i
geekfromthefutur
  • geekfromthefutur
So what we went over was for this one
geekfromthefutur
  • geekfromthefutur
but the one you said it should be that was for the middle one
jim_thompson5910
  • jim_thompson5910
yeah the solution to #2 is x = i or x = -i

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