Plz help with these questions to see if im right

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Plz help with these questions to see if im right

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

we have to determine if the equation has real or imaginary solutions by solving

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

show what you have so far
Well i only have the first one and i said it was a real soultions
yes that first one definitely has 2 real solutions. Were you able to find the actual solutions?
with the 3rd equation start by subtracting 9 to get (x^2=-6)
yea well i didi have it written down
ok show us your work please
the soluion would come out to a decimal if you work the rest out thats your hint for question 3
x= ± 2 21−−√ 7 x≈1.30930734,−1.30930734
thats all i havee for number 1
for number two i have this hold on
x=±i6√
i say spot one because of the simplification it checks out
so i think number two is imaginary soutions bevause of the i in the answer
#2 does have imaginary (aka non real) solutions but it's not x=±i6√
What is it
then again i am shorting out from the day i had at school with 3 tests so im good for a few helpings tonight
after you distributed, what did you get?
i just put it in a math solver
1 Attachment
0 doennt equal -3
oh, so you're working on #3 then
nope still 2nd
im worked out the second one and got 0=-3 and thats not possible
i'm referring to this one as the second (since you posted it second) http://assets.openstudy.com/updates/attachments/56020960e4b0ad22e8a696f9-geekfromthefutur-1442974199899-win_20150922_220854.jpg
Ohhh sorry my bad yea we are working on the 3rd one my bad
square root 6
How would i write this in two little lines catman
sorry my pc just crashed but it restarts fast
ok
you round the decimal to the nearest hundreth
so it would be 2.45 instead of 2.449
ok
Wait what decimal
the square root of 6
is not a whole number
2.44948974278
but instead it would be 2.45 as you round the 9 to the 2.44 to a 2.45. note you cannot round up a if the number behind it is less than five for example if the number was 32 it cannot be rounded to 40 it would round down to 30
ok and what about the next problem
you mean #3?
yea
if you subtract 9 from both sides, you'd get x^2 = -6 taking the square root of both sides leads to what your solver got
ok x=i,−i
so imaginary
no it should be \[\Large x = \pm i*\sqrt{6}\]
oh ok
Real quick @jim_thompson5910 this went for this one?
oh, I see now yes, the solution to that one is definitely x = i or x = -i
So what we went over was for this one
but the one you said it should be that was for the middle one
yeah the solution to #2 is x = i or x = -i

Not the answer you are looking for?

Search for more explanations.

Ask your own question