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geekfromthefutur

  • one year ago

Plz help with these questions to see if im right

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  1. geekfromthefutur
    • one year ago
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    we have to determine if the equation has real or imaginary solutions by solving

  2. geekfromthefutur
    • one year ago
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  3. geekfromthefutur
    • one year ago
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  4. geekfromthefutur
    • one year ago
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    @jim_thompson5910 @surjithayer

  5. jim_thompson5910
    • one year ago
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    show what you have so far

  6. geekfromthefutur
    • one year ago
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    Well i only have the first one and i said it was a real soultions

  7. jim_thompson5910
    • one year ago
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    yes that first one definitely has 2 real solutions. Were you able to find the actual solutions?

  8. TheCatMan
    • one year ago
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    with the 3rd equation start by subtracting 9 to get (x^2=-6)

  9. geekfromthefutur
    • one year ago
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    yea well i didi have it written down

  10. jim_thompson5910
    • one year ago
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    ok show us your work please

  11. TheCatMan
    • one year ago
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    the soluion would come out to a decimal if you work the rest out thats your hint for question 3

  12. geekfromthefutur
    • one year ago
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    x= ± 2 21−−√ 7 x≈1.30930734,−1.30930734

  13. geekfromthefutur
    • one year ago
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    thats all i havee for number 1

  14. geekfromthefutur
    • one year ago
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    for number two i have this hold on

  15. geekfromthefutur
    • one year ago
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    x=±i6√

  16. TheCatMan
    • one year ago
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    i say spot one because of the simplification it checks out

  17. geekfromthefutur
    • one year ago
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    so i think number two is imaginary soutions bevause of the i in the answer

  18. jim_thompson5910
    • one year ago
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    #2 does have imaginary (aka non real) solutions but it's not x=±i6√

  19. geekfromthefutur
    • one year ago
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    What is it

  20. TheCatMan
    • one year ago
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    then again i am shorting out from the day i had at school with 3 tests so im good for a few helpings tonight

  21. jim_thompson5910
    • one year ago
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    after you distributed, what did you get?

  22. geekfromthefutur
    • one year ago
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    i just put it in a math solver

  23. geekfromthefutur
    • one year ago
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  24. TheCatMan
    • one year ago
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    0 doennt equal -3

  25. jim_thompson5910
    • one year ago
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    oh, so you're working on #3 then

  26. geekfromthefutur
    • one year ago
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    nope still 2nd

  27. TheCatMan
    • one year ago
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    im worked out the second one and got 0=-3 and thats not possible

  28. jim_thompson5910
    • one year ago
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    i'm referring to this one as the second (since you posted it second) http://assets.openstudy.com/updates/attachments/56020960e4b0ad22e8a696f9-geekfromthefutur-1442974199899-win_20150922_220854.jpg

  29. geekfromthefutur
    • one year ago
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    Ohhh sorry my bad yea we are working on the 3rd one my bad

  30. TheCatMan
    • one year ago
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    square root 6

  31. geekfromthefutur
    • one year ago
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    How would i write this in two little lines catman

  32. TheCatMan
    • one year ago
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    sorry my pc just crashed but it restarts fast

  33. geekfromthefutur
    • one year ago
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    ok

  34. TheCatMan
    • one year ago
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    you round the decimal to the nearest hundreth

  35. TheCatMan
    • one year ago
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    so it would be 2.45 instead of 2.449

  36. geekfromthefutur
    • one year ago
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    ok

  37. geekfromthefutur
    • one year ago
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    Wait what decimal

  38. TheCatMan
    • one year ago
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    the square root of 6

  39. TheCatMan
    • one year ago
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    is not a whole number

  40. geekfromthefutur
    • one year ago
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    2.44948974278

  41. TheCatMan
    • one year ago
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    but instead it would be 2.45 as you round the 9 to the 2.44 to a 2.45. note you cannot round up a if the number behind it is less than five for example if the number was 32 it cannot be rounded to 40 it would round down to 30

  42. geekfromthefutur
    • one year ago
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    ok and what about the next problem

  43. jim_thompson5910
    • one year ago
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    you mean #3?

  44. geekfromthefutur
    • one year ago
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    yea

  45. jim_thompson5910
    • one year ago
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    if you subtract 9 from both sides, you'd get x^2 = -6 taking the square root of both sides leads to what your solver got

  46. geekfromthefutur
    • one year ago
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    ok x=i,−i

  47. geekfromthefutur
    • one year ago
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    so imaginary

  48. jim_thompson5910
    • one year ago
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    no it should be \[\Large x = \pm i*\sqrt{6}\]

  49. geekfromthefutur
    • one year ago
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    oh ok

  50. geekfromthefutur
    • one year ago
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    Real quick @jim_thompson5910 this went for this one?

  51. jim_thompson5910
    • one year ago
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    oh, I see now yes, the solution to that one is definitely x = i or x = -i

  52. geekfromthefutur
    • one year ago
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    So what we went over was for this one

  53. geekfromthefutur
    • one year ago
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    but the one you said it should be that was for the middle one

  54. jim_thompson5910
    • one year ago
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    yeah the solution to #2 is x = i or x = -i

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