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distribute the equation first of all
I'm actually doing the same exact problems as you are right now in algebra
as shavonnah is saying, multiply the outer 2 by each term inside the parenthesis |dw:1442974931673:dw|
8 and 5? I have no idea.. BRAIN FART
I can show you what I got. I worked it out on paper but I'm not sure if it's correct
Please due. Im kind of lost..
\[4x-8=2(2x-3) second process.. 4x-8=4x+-6 third process 8x-8=+-6 third and final step 8/2=4 so x=4\]
I don't think that's correct..
its multiple choice in my book, thats not an option.
I wasn't trying to be rude.. I'm a junior too. Also in college
Notice how the 4x terms cancel |dw:1442975852372:dw|
So was I right with the x=-6?
we're left with the equation `-8 = -6` which is always false. -8 and -6 are two different numbers that aren't equal So that means there is no solution. There are no numbers we can replace x with to make a true equation. It's impossible
4x -8=2(2x-3) 4x - 8 = 4x-6 4x = 4x + 2 no possible solution
and by "the 4x terms cancel" I mean, subtract 4x from both sides 4x-4x = 0x = 0 which goes away
Oh!! Its a.. let me think.. lol I forgot what its called..
you might be searching for the term "inconsistent"
inconsistent equations have no solutions
is an equation with no solution.
there you go
Contradiction works too