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amonoconnor
 one year ago
How do you simply the following expression:
(((sqrt(6x))2)/((sqrt(3x)1)))*(((sqrt(3x))+1)/((sqrt(3x))+1)))
Thank you very much! Any and all help is greatly appreciated!
amonoconnor
 one year ago
How do you simply the following expression: (((sqrt(6x))2)/((sqrt(3x)1)))*(((sqrt(3x))+1)/((sqrt(3x))+1))) Thank you very much! Any and all help is greatly appreciated!

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Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{\sqrt{6x}2}{\sqrt{3x}1}\times \frac{\sqrt{3x}+1}{\sqrt{3x}+1}\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1In the denominator of the first fraction: is it 1or +1

jackthegreatest
 one year ago
Best ResponseYou've already chosen the best response.0well for one u can cross out the equation on the right, the top and bottom r exactly the same

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0Shoot.. you are correct. "1"

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1If the problem is as I have posted it the denominators are of the form (ab)(a+b) and that is equal to a^2b^2

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0I know, that's the point: Multiplying by the conjugate, but I'm weary as to how to multiple that across... ?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1So the denominator is 3x1or 2x

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1now let's do the numerator multiplication:

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0How did you get that? :/ I'm not disagreeing, I just don't know how you worked it out..

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1\[(\sqrt{6x}2)(\sqrt{3x}+1)=\sqrt{(6x)(3x)}+\sqrt{6x}2\sqrt{3x}2\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1Where did that come from?

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0Isn't that what'll be under the radical, in the first term in the numerator? :/

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0Dude, I'm tired.. my bad again.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1so put that numerator over 2x and you are done.

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0Can we cancel out anything else?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1Are there any common factors?

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442976045683:dw

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0Is this all correct, and the final version?

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442976240464:dw

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0This is totally wrong, right?

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0The second version is correct as well??

amonoconnor
 one year ago
Best ResponseYou've already chosen the best response.0That was my initial, instinctual way to multiple the numerator across, but I thought for sure it was wrong, and I understand how you first showed me, foiling the polynomials UNDER the radical, getting 18  9x + x^2. But are you saying that my instinctual way works?
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