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Is that the problem?
In the denominator of the first fraction: is it -1or +1
well for one u can cross out the equation on the right, the top and bottom r exactly the same
Shoot.. you are correct. "-1"
If the problem is as I have posted it the denominators are of the form (a-b)(a+b) and that is equal to a^2-b^2
I know, that's the point: Multiplying by the conjugate, but I'm weary as to how to multiple that across... ?
So the denominator is 3-x-1or 2-x
now let's do the numerator multiplication:
How did you get that? :/ I'm not disagreeing, I just don't know how you worked it out..
What is (a-b)(a+b)
(18 - 9x + x) :)
Where did that come from?
Isn't that what'll be under the radical, in the first term in the numerator? :/
It would be 18-9x+x^2
Dude, I'm tired.. my bad again.
so put that numerator over 2-x and you are done.
Can we cancel out anything else?
Are there any common factors?
Is this all correct, and the final version?
This is totally wrong, right?
it is correct.
The second version is correct as well??
That was my initial, instinctual way to multiple the numerator across, but I thought for sure it was wrong, and I understand how you first showed me, foiling the polynomials UNDER the radical, getting 18 - 9x + x^2. But are you saying that my instinctual way works?