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anonymous

  • one year ago

Given the geometric sequence where a1 = 3 and the common ratio is −1, what is the domain for n? All integers where ≤ 0 All integers where n ≥ 0 All integers where n ≤ 1 All integers where n ≥ 1

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. anonymous
    • one year ago
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    i got C:)

  3. jim_thompson5910
    • one year ago
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    The domain of any arithmetic or geometric sequence is \(\Large n > 0\) or \(\Large n \ge 1\) where n is an integer. The reason why is because n is a counting number which indexes the terms n = 1 refers to the first term n = 2 to the second term n = 3 is the third term etc

  4. anonymous
    • one year ago
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    then that narrows it down to b or d

  5. anonymous
    • one year ago
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    So then, the answer would be B. Right?

  6. jim_thompson5910
    • one year ago
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    it's NOT b because \(\Large n \ge 0\) includes n = 0 but we don't start with n = 0. We start with n = 1

  7. anonymous
    • one year ago
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    Oh so 0 isn't a natural #?

  8. jim_thompson5910
    • one year ago
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    nope

  9. anonymous
    • one year ago
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    Ok. I get it now:) Thanks!

  10. jim_thompson5910
    • one year ago
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    natural numbers = counting numbers counting numbers = 1,2,3,4,...

  11. anonymous
    • one year ago
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    Oh! Yeah that's true! You dont start w/ ero when you count:)

  12. jim_thompson5910
    • one year ago
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    yeah and when you say "first term" it's natural to think of 1 as the first thing if you made 0 first, then 1 would be second. That's a bit confusing

  13. anonymous
    • one year ago
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    Hm I didn't think of it like that! But yeah, that's true

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