Given the geometric sequence where a1 = 3 and the common ratio is −1, what is the domain for n? All integers where ≤ 0 All integers where n ≥ 0 All integers where n ≤ 1 All integers where n ≥ 1

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Given the geometric sequence where a1 = 3 and the common ratio is −1, what is the domain for n? All integers where ≤ 0 All integers where n ≥ 0 All integers where n ≤ 1 All integers where n ≥ 1

Mathematics
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i got C:)
The domain of any arithmetic or geometric sequence is \(\Large n > 0\) or \(\Large n \ge 1\) where n is an integer. The reason why is because n is a counting number which indexes the terms n = 1 refers to the first term n = 2 to the second term n = 3 is the third term etc

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then that narrows it down to b or d
So then, the answer would be B. Right?
it's NOT b because \(\Large n \ge 0\) includes n = 0 but we don't start with n = 0. We start with n = 1
Oh so 0 isn't a natural #?
nope
Ok. I get it now:) Thanks!
natural numbers = counting numbers counting numbers = 1,2,3,4,...
Oh! Yeah that's true! You dont start w/ ero when you count:)
yeah and when you say "first term" it's natural to think of 1 as the first thing if you made 0 first, then 1 would be second. That's a bit confusing
Hm I didn't think of it like that! But yeah, that's true

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