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Fanduekisses

  • one year ago

Graph Transformations: What does a negative sign do to an absolute value graph if it's in front of the || ?

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  1. Fanduekisses
    • one year ago
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    I know that if it's in fron of the x it flips the graph. What about in this case: \[-|-x-3|+2\]

  2. zepdrix
    • one year ago
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    When the negative is on the x, it flips it `horizontally`. Example: \(\large\rm f(x)=\sqrt{x}\) would flip across the y-axis if we did this: \(\large\rm g(x)=\sqrt{-x}\) A negative played on the outside of everything, is really just a negative being placed on y. And it results in a flip `vertically`. Example: \(\large\rm j(x)=x^2\) would flip across the x-axis if we did this: \(\large\rm k(x)=x^2\) But with your problem, notice that we have neither of these things happening. We're not applying the negative to the 2. So normally I would say, we're reflecting the graph about the x-axis. But in this case, we're reflecting the graph about the line y=2.

  3. zepdrix
    • one year ago
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    Woops, \(\large\rm k(x)=-x^2\)

  4. Fanduekisses
    • one year ago
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    Ohh so in this case it flips both horizontally and vertically?

  5. zepdrix
    • one year ago
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    |dw:1442976962331:dw|The \(\rm \color{green}{green}\) is the original function. The \(\rm \color{blue}{blue}\) is the new one. The function is being reflected vertically across the \(\rm \color{#DD4747}{pink}\) line.

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