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Fanduekisses
 one year ago
Graph Transformations: What does a negative sign do to an absolute value graph if it's in front of the  ?
Fanduekisses
 one year ago
Graph Transformations: What does a negative sign do to an absolute value graph if it's in front of the  ?

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Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0I know that if it's in fron of the x it flips the graph. What about in this case: \[x3+2\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2When the negative is on the x, it flips it `horizontally`. Example: \(\large\rm f(x)=\sqrt{x}\) would flip across the yaxis if we did this: \(\large\rm g(x)=\sqrt{x}\) A negative played on the outside of everything, is really just a negative being placed on y. And it results in a flip `vertically`. Example: \(\large\rm j(x)=x^2\) would flip across the xaxis if we did this: \(\large\rm k(x)=x^2\) But with your problem, notice that we have neither of these things happening. We're not applying the negative to the 2. So normally I would say, we're reflecting the graph about the xaxis. But in this case, we're reflecting the graph about the line y=2.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2Woops, \(\large\rm k(x)=x^2\)

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0Ohh so in this case it flips both horizontally and vertically?

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2dw:1442976962331:dwThe \(\rm \color{green}{green}\) is the original function. The \(\rm \color{blue}{blue}\) is the new one. The function is being reflected vertically across the \(\rm \color{#DD4747}{pink}\) line.
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