At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
what does it mean if the function has a stationary point?
Stationary point means the derivative of that function is zero.
Well, I just know that if a function has a stationary point then the derivative of that function is equal to 0.
oh... you already said that lol
Did you find b already or not?
Nope, not yet.
I don't know what to do.
Should I just plug in (2,3) to the function to solve for B?
If so, then I'll get B=-13. But I'm not sure.
this is not just about plugging in values you need to know what you're doing and why you're doing it
Yeah, that's why I am asking how to do it. :)
You should start with taking the derivative, set it equal to zero
how should not be the point of interest
Okay, I'll show my work.
set x=-2 and f(x) =3
^ that's what I did to find B.
Hmm..I don't think you can just leave out B
we know that in a graph |dw:1442978750479:dw|
a and b are constants...
@Jhannybean Well, B is a constant. SO the derivative is 0.
Oh, didn't see the derivative sign in your function, m'bad.
You didn't? That's fine. :D
After you solve for a and got -12 plug that to the original equation and dont forget to plug (-2,3) for x and f(x). From there, you can solve for b.
^ I did that and I got -13.
just like what I said a while ago :D
Okay, then you are good to go :)
Awesome! Thanks for the help though! :)
I actually just found out that stationary points are critical points based on this problem. I heart openstudy