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@Abhisar for the first question this is what i did...
first i figured out the normal force the earth was exerting the block of wood. Normal force = mass x gravity normal force = 0.72Kg X 9.80m/sec^2 Normal force = 7.05N This is my normal force.
from here i used te frictional formula to get my force of friction. Force of friction = μk x 7.05N Force of friction = 4.51N i got my friction.
Nor that i ad my frictinal force and normal force. i plugged them into te formula to get my net force Applied force - frictional force = m x change in velocity/time Applied force - 4.51N = 0.72Kg x 0.8m/sec^2 Applied force = 4.51N + 0.57N Applied force = 5.08N HEre is te answer to my first question....
i just wanna know to find the net force of the block of wood..... my actual force is 5.08N and frictional force is 4.51N Therefore the net force would be 5.08N - 4.51N = 0.57N right?!?!?!
net force = 0.57N?!?!?!?!
Actually the question says that table is smooth so that means frictional force will not act. In this case force on the block will solely due to the push of boy. Since, block has a velocity of 1.6 after 2 seconds, its acceleration will be 0.8 Therefore, Force = 0.72 x 0.8 = 0.576 N
but bay did you read the last part of the question....."the kinetic friction is 0.64.
It's fine if you want to consider the friction in. the answer will still be same.
ok but to get the net force, do i subtract applied force from frictional force?!?!?!
i'm getting about the same answer so ....LOL
Net force = Applied Force - Frictional force.
ok thank you shooooooomuch i love you. :")
So, Applied Force = Net Force + Frictional force.
Note: In the first part we calculated the net force. In second part we calculated the frictional force Finally in the third part we calculate the applied force by adding net force and frictional force...
yes yes yes!!! :"D
Thanks honey, i appreciate your effort....!!