What is the sum of the geometric sequence –4, 24, –144, ... if there are 6 terms? How do I do this?

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What is the sum of the geometric sequence –4, 24, –144, ... if there are 6 terms? How do I do this?

Mathematics
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Ok, the equation looks like this: \[S _{n}=a _{1} \frac{ 1-r ^{n} }{ 1-r }\]
what's S, A, R, and N?
S= the sum n=the term that you choose, so for this example it would be 6 \[a _{1}\]= the first term

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So exactly how would you set it up? thats all I need to know, can you show me an example?
Let's break it down a little bit, so it's not so much to take in. We just fill in what we know so: \[S _{6}= -4 \frac{ 1-(-6)^{6} }{ 1-(-6)}\]
I forgot to tell you that we get "r" by 24/-4=-6 because that's our ratio.
This equation does not work @Meehan98 If you try to do for the second term (S2), will hit as the number 20, which is not consistent with the case
Just find the pattern In this case its multiplying by -6
Sohal i'm in trigonometry, i'm not just doing x-6 lol
so the answer would be... 864,-5184,31104 would be the next numbers
Lol but all the information is informant of you -_- and the way you get the answer doesn't matter as long as you don't cheat,show work,and get the right answer
do you deny that I got the right answer?
I found the answer deductivly
Ps I never actually got the answer But I did give you the next numbers of the sequence
hmm..this doesn't make sense then. I've been doing these problems all day without an issue..
ok do it your way ill do it my way -_- honestly ever herd of doing it in different methods forget it
I know; because the formula that I have up there is the Sum Formula so it wouldn't make sense to fit the second term in there. The formula for the terms is:\[a _{n}=a _{1} r ^{n-1}\]
If you get the second number and divide by the first, will result 6. If you made the third number and divide by the first, will result in 36, which is 6 ^ 2, we can quickly realize the equation, that is: \[n = 4 x (-6^{(n-1)})\] where: n = number wish to find So, \[n1= -4 . (-6^{1-1}) = -4 . (1) = -4\]\[n2= -4 . (-6^{2-1}) = -4 . (-6) = 24\]\[n3= -4 . (-6^{3-1}) = -4 . (36) = -144\]\[n6= -4 . (-6^{6-1}) = -4 . (-46656) = +186624\]
we can quickly realize the equation, that is: n=-4x(−6(n−1))***** << I forgot -4 there

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