A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
A uranium238 atom can break up into a thorium234 atom and a particle called an alpha particle, α4. The numbers indicate the inertias of the atoms and the alpha particle in atomic mass units (1 amu = 1.66 × 10−27 kg). When an uranium atom initially at rest breaks up, the thorium atom is observed to recoil with an x component of velocity of 2.9 × 105 m/s. How much of the uranium atom's internal energy is released in the breakup?
anonymous
 one year ago
A uranium238 atom can break up into a thorium234 atom and a particle called an alpha particle, α4. The numbers indicate the inertias of the atoms and the alpha particle in atomic mass units (1 amu = 1.66 × 10−27 kg). When an uranium atom initially at rest breaks up, the thorium atom is observed to recoil with an x component of velocity of 2.9 × 105 m/s. How much of the uranium atom's internal energy is released in the breakup?

This Question is Closed

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0"The numbers indicate the inertias of the atoms ... " Which numbers?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442991985117:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So how would I figure this out?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I understand what the inertias are because you just multiply 238, 234, and 4 by 1.66x1027

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0what are the moments of inertia?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.