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anonymous
 one year ago
96a24a^2
Do I have to rearrange this?
anonymous
 one year ago
96a24a^2 Do I have to rearrange this?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's a factoring question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh. yeah (24a^2+6a9) take out the common factor 3 3(8a^2+2a3) so this is a "hard factoring problem"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0try... 2 and 4 for a, and 3 and 1 for the constant.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm really confused by this. Would appreciate greatly any help. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm a bit confused about what you did, hedgepig. Perhaps I need to review your text for a bit. If you could, please do stay. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so what is the way to figure out the order?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0first, you want to factor out the largest constant.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What comes first? A, AB, or B? This is just in general.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is a squared before a?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.096a24a^2 factor out the largest number you can first.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, but I guess I just need to know, in general, the rule for how you order things. Because, I have more problems, of course.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, it's just, if you wouldn't mind, I'd like to know how to properly order this trinomials.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there are multiple ways to process this, but, we can do that too. Order from highest degree to lowest.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But I don't what's highest. Is a^2 higher or lower than a?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it? what is the degree of a^2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a^2 is a x a, but I don't know whether it would come before or after a.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If I were to guess, I would say after.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would say a exponents, followed by B. I would guess ab would come before B, too.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0from what I gather you're missing knowledge from polynomials and terminology. Do you what the degree of a term is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Unfortunately, I am not very knowledgeable on the terminology.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok. You NEED to know this stuff. that being said, it shouldn't be too hard. let's do some examples: 6x^3 23x^5 x^3 8x 9 5x^2 identify the degree of each term.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would guess the degree is the exponent.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, degrees are synonymous with exponents?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what we are referring to is, as far as I can tell, a specific realm  the realm of polynomials.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to answer your question, yes, degree is synonymous with exponents in the context of polynomials, but I am not sure I would say x^(pi) would have degree pi.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In the poly and trinomial universe, degrees and exponents are the same thing.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's the universe my head is in right now. :P

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's not a problem in this context, but I would really advise you think broader than this if you want success mathematically.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now, I really do need to know how to order these trinomials, because they're giving them to me out of order. If I can understand how the order works, it should be easy.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i already gave you the answer to this  you order them from highest degree to lowest.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The problem is, I genuinely do not know what the highest degree is. I don't.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0note that for expression x^4 y^2 z^7 the degree is 4+2+7=13

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. That is, again, why i told you to identify the degree of each term.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06x^3 23x^5 x^3 8x 9 5x^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0of what degree? and you forgot a minus sign.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The other two don't have a degree, though.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand why you keep ignoring me. Identify the degree of each term 6x^3 23x^5 x^3 8x 9 5x^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The degree is the 2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry, I'm not trying to ignore you.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The degree isn't the 2 in that case. The degree IS 2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442986372632:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. 3, 2. 5, 3.3, 4. IDK, 5. IDK 6. 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it might be hard (I know I had a bit of trouble with exponents in the beginning) but you really need to know how to identify and visualize what's going on here.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.096a24a^2 Is 24a^26a+9

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for term ax^n for constant a and n, the coefficient is equal to a and the degree is equal to n for term bx^n y^m the coefficient is b and the degree is equal to n+m

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes... but, what I don't understand is how you are able to factor without knowing how to order polynomial terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Perhaps that was the only reason I was having confusion. I would like to work on the problem a bit, see if I get it right, and you can confirm.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, I guess we'll see if I know how to factor. I think I do, though. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer is aways above if you wish to check it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, but I do want to do it myself.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my suggestion to you, if you are so dedicated and inclined, and if you wish to have future success in mathematics, is to review prealgebra

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there are plenty of resources available online for free to do so...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Anyways, if I did this correctly, I have to think of two factors that add to 6 and when multiplied, are 216. Is this what I am supposed to do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where are you getting 216

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so... am I to square the first and last number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually, let me think, I have never learned how to factor that way.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, 24 isn't a perfect square. So, honestly, I have no idea what to do from here.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nope, that doesn't look right at all.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was walking you through the problem step by step, but I must've gone too quickly.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you understand the purpose of factoring trinomials, and what the inverse operation of that is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My understanding is that the purpose of factoring is to simplify.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The inverse operation, I would assume how we're all familiar with foil, well the inverse operation would be the system to get a trinomial in into the state of foil. How it's implemented, though, I'm not sure.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well why don't we look at it. let's foil (ax+b)(cx+d) what do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got acx^2+axd+bcx+bd

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. that's equal to (ac)x^2+(ad+bc)x+(bd) right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0remember our expression 24a^2 6a+9 ? here is what factoring really is. ac=24 6=ad+bc 9=bd Solve the system for a, b, c, and d

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand the question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Note that, once we have the solution, we know that the factored form of the expression is simply (ax+b)(cx+d)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You want me to tell you which each letter signifies individually? I don't know how to do that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no. I just gave you a system of equations.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ac=24 6=ad+bc 9=bd

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, I don't understand what that is asking.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0find values of a, b, c, and d such that each of the three equations holds true

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Give me a minute, please. Thank you.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is how I got the system by the way: (ac)x^2+(ad+bc)x+(bd) 24a^2 6a+9 the variable a is redudant but for the second equation take x=a to get (ac)x^2+(ad+bc)x+(bd) 24x^2 6x+9 well, (ac)x^2+(ad+bc)x+(bd) (24)x^2+(6)x+(9) thus, (ac)=(24); (ad+bc)=(6);(bd)=(9)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0by the way, here is a hint: you should not try to solve the system of equations using algebra. Use trial and error.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. :) I knew that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and what will our factored expression be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what did I tell you to foil?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, I do get stressed when I work on math. My brain usually isn't at its peak at this point.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you are doing just fine  I am not approaching this problem in the standard way that most people learn how to factor... I choose not to do so because you will learn the standard way from everyone else...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You wanted me to foil (ax+b)(cx+d)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok... so simply resubstitute your values for a, b, c, and d, no?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I don't understand. I didn't figure out the meaning for an X.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I do appreciate you trying to be innovative in your explanation, but perhaps the standardized explanation is so for good reason?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0mmm this is a key point that most people struggle with algebra. We first introduce letters that represent numbers in algebra. Well, we often tell people to evaluate expressions by assigning them values for particular letters. Here's the thing though  there are basically two kinds of symbols: symbols that represent CONSTANT numbers and symbols that represent UNKNOWN numbers. You might wonder, why is it that we need symbols for CONSTANT numbers? Consider the polynomial of degree two ax^2+bx+c There are infinitely many polynomials of this form. here are a few. x^2+3x3 10x^212x+5 but what about x? we don't actually have any fixed value for x, so we leave it as is, despite knowing what a, b, and c are. In this case, i have given you an expression with a, b, c, d, and x and we have found values for a, b, c, d... but not x... why is it that we do not know what to do for x? Simple. Let's look at the original problem. 96a24a^2 note that halfway through I turned the a's to x's. No matter. From the start, we defined a (x right now) as a symbol that varied. There is no way to find it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The standardized explanation is why many of my peers struggled deeply with calculus  not because they could not follow the rules of calculus, but because they could not CREATE expressions from understanding algebraic motivations.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am not saying not to look at the standardized explanation  I have a pretty good site I will refer you to after this, but we are almost at the end of this exercise.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, by all means continue. You know what you're doing. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.024^26a+9 I just don't know how to factor it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for (ax+b)(cx+d) the substitution a = 6 c = 4 b = 3 d = 3 yields? do not worry about foiling the result

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. I will do that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You basically just factored the expression. Now, there is one last step we must perform to call out expression factored. We can actually factor 3 out from the first parenthetical

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would be (2x+3)(2x+3)3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes.. but when you have a factored expression, you actually put any constants to the very front. so your 3 belongs in the front of everything.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and I think you meant, for the second parenthetical, 4x+3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so how do I do with a trinomial?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The original problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I still honestly don't know what to do.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just became you're first fan, by the way.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hahaha I am on an alt, but, yes, first fan on this account :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(2x+3)(2x+3)3 move the negative three to the other side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry we are really close to the answer and I don't want to steal it from you by typing it ahaha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the second parenthetical should be 4x+3... you miscopied it before and I did the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(6x+3)(4x+3) >(2x3)(4x+3)*3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Did I do it correctly?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah... you just went about my roundabout method of factoring the expression (and you got it right! though those x's are supposed to be a's :P http://www.wolframalpha.com/input/?i=factor+96a24a%5E2+ ). if you wish, you can remultiply to ensure that it is correct. but, as I promised, here are some links to help you with factoring this is the homepage of the site I learned algebra from http://www.purplemath.com/modules/index.htm http://www.purplemath.com/modules/factquad.htm here is the famous khan academy https://www.khanacademy.org/math/algebra/introductiontopolynomialsandfactorization/factoringpolynomials2quadraticforms/v/factoringpolynomials1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pertaining DIRECTLY to what we just did is http://www.purplemath.com/modules/factquad2.htm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, but I still don't know how to do the original problem, it's a trinomial.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0all of those links deal with trinomials. quadratic refers to the fact that they have maximum degree 2.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You know, I sometimes do need a little bit of a different approach.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you tell me what is the step you would take in solving the original problem now that we know the proper order?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0here is a computer generated solution manual

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0note that this is also called factoring by grouping

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I saw the next step. I didn't see the answers. I'll like to see if I got it right. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, let's see if I get this! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0mmhmm  I think this site has the lesson you are looking for fyi http://www.purplemath.com/modules/factquad2.htm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Working on it. Hope you stay. :) Thank you so much for your time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, did 3 HAVE to be factored out? My natural proclivity was to factor 3.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha no problem thanks for bearing with me even when it hasn't been apparent where I've been taking the discussion. unfortunately, it's around 2:50AM and I have a chemistry class tomorrow at 9AM, so I should probably head off to bed. As for 3, it is standard to make the leading coefficient (the number in front of the a^2 in this case) to be positive, because otherwise all the other signs have to be switched while you try to factor.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the point of using 3 was to make it so the number in front of a^2 was positive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. Are you in college? What year are you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm a freshman in college.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, okay. Yeah, I better let you sleep. It is important.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0best of luck to you  feel free to respond to those post if you have anymore questions, though I would actually suggest you open a new question with the same problem and have some other persons look at it  they will give a much more straightfoward way of explaining how to factor.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0undeclared engineering  are you in college?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nope. Junior in high school.This is Algebra 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does my work seem college level? :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, but you would be surprised as to the number of students who take "college algebra" which is merely junior high school algebra in college. Your work does not seem college level, but your vocabulary does seem so.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm a bit confused as to what to do with +6 and 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you illustrate that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry, I hate to take up your sleep, but hopefully, once I'm certain how to do one question, I'll know how to do them all.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, you have the expression (8a^2+2a3) well, let's look at (ax+b)(cx+d)=(ac)x+(cb+ad)x+(bd) note that this is saying we search for two numbers that have a product of 8. (ac=8) we search for two numbers that have a product of 3 (bd=3) we seek to make ad+bc equal to 2. this is where the 6 and 4 come in. 64=2, which means ad=6 and bc=4, or ad=4 and bc=6.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0why did we pick 6 and 4? well, it was a natural choice because if we look at the factors of 8, we have 2 and 4 and 1 and 8. if we look at the factors of 3, we have 1 and 3 or 1 and 3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, I know how to get the factors, but I don't know what to do with them.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, there are a lot of choices for the factors of 8, so we will worry about the factors of three instead.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thus we wind up with something like (?a+3)(?a1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, we will wind up with 3?a?a such that we get 2a when we pick two question marks. note the question marks have to multiply to 8. because ?a*?a=8a^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My guess, would be (8a^2+6) (43) (1) 43 is 1, which we can cross off, so 3(8a^2+6)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hold on... the answer 3(8a^2+6) is not what we originally looked at. if you simplify that, you get somethign different fromt he original expression.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know, going to need your explanation skills 'cause I'm lost.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Says you've been typing for a while.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0let's start over. we just factored out that 3 3(8a^2+2a3) so let's worry instead about factoring 8a^2+2a3. Well, all this is asking you to do is to rewrite 8a^2+2a3 in the form (ra+t)(qa+s) well, factoring is kinda one of those things wher eyou guess and check. we can foil out our expression to visualize it better though. we'll get (rq)a^2+(tq+rs)a+ts compare it with 8a^2+2a3 in note that 8 HAS to equal rq and 3 HAS to equal ts and 2 HAS to equal tq+rs. Why? because our expression is in the most simplified form possible. we know that all the like terms have been combined, so we can match the coefficients safely. it then boils down to solving the system. to do so, let's compare the pairs rq and ts and see which one has fewer potential factors. the factors of 8 are 1,2,4,8 (or 1,2,4,8) while the factors of 3 are (1,1,3,3) so let's start with picking arbitrary factors of three for our values ts. so, let's say t=3, and s=1 then, we have (ra+t)(qa+s) > (ra+3)(qa1)=8a^2+2a3 well we know they already multiply to 3 because we chose them to. however, we're gonna have to make additional constraints to this problem if we want to get anywhere. let's pick values for r and q. remember rq=8, so let's just do r=2 and q=4 then (2a+3)(4a1)... well we are really just trialing and erroring for the value tq+rs. in this case we get tq=12 and rs=2 tq+rs=10. We're supposed to get 2. so, let's think... how can we get 2? well, it just so happens that if tq=6 and rs=4, we'll get 2. That intuition comes with expreience, but that is the origin of the 6 and 4. knowing that, it follows that because ts=3, t=3, and q=2. whereas, s=1, and r=4 that is the solution in this case, which you deducted earlier actually.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, I know how to figure out the factors. That's easy to me.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.06 and 4. I struggle with what to do with the factors, though.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is my struggle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm fine with the guess work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.08a^2+2a3 and we have 6 and 3. I don't know what to do from here.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just resubstitute. again, with the expression (ax+b)(cx+d) you will get acx^2+(ad+bc)x+bd...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0your 6 and your 4 are, respecitvely, your ad and your bc in this instance.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So (8a^2+6) and (43). Is that right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0... no  foil the result and you will quickly learn that that does not yield what you need it to I am not sure i can do a good job explaining this... I would advise you check out some videos on khan academy. I am basically out of time but not done explaning, so I will give you this video which uses another method (factoring by grouping) and hope it will help. It's 5 minutes... https://www.khanacademy.org/math/algebra/introductiontopolynomialsandfactorization/factoringpolynomials2quadraticforms/v/factoringtrinomialsbygrouping6 if you have time, I'll be online very shortly tomorrow morning.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Funny you say that, as I am studying French.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If I could have I would've asked you to show your work that got you to that result, but unfornuately I really am out of time  no point in me showing up to chem class if I can't even think

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Fair enough. Thank you so much for staying as long as you did; I'm sure it was frustrating dealing with me.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I "studied" french  all i remember are the very, very basics now, unfortunately. There was no frustration dealing with you by the way  it is incomparable how often I get frustrated with entitled kids who come on this site demanding answers with neither appreciation nor patience. You have a good degree of both, and you are one of the rare cases where the teacher leaves before the student. I will admit that I am somewhat frustrated though  not at you for not understanding the concept, but at myself for not being able to articulate that which i supposedly find so straightfoward and easy to do. Farewell!
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spraguer
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