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so the temperature of the water has risen by \(45-22 = 23^{\circ}C\)

that's the delta t right?

Yes, then the heat added to the water is given by,
\(Q=c*m*\Delta t=4.18*42800*23 = 4114792 J\)

That means the bar has lost the same amount of heat.
You can use that to find the mass of bar

Oh I see.

0.446 is specific heat of iron is it ?

yeah

Looks good !

thanks can you also help me with this one?

looks like a similar problem..
give it a try

Energy released by water = Energy absorbed by aluminium pan

\[4.18*752*\Delta t = 0.9*1000*13 \]
you can solve \(\Delta t\)

oh okay
and would that be 39-26?

wait hold on

what do you get for \(\Delta t\) ?

3.72 Celsius...

good
\(\Delta t = 3.72 \)
and you know that final temperature = \(39\)
so initial temperature = ?

so subtract?

Yep, 42.72 C looks good

I am confused about what calories are.

25 kj/ grams
2800 kilocalories of energy a day
we are finding mass

google gave me
1 kilocalorie =
4184 joules

yeah i think a calorie is like 4.18 something per joules.

right, so 2800 kilocalories = how many kilojoules ?