A hare, pursued by a grey-hound is 24 of her own leaps ahead of him. While the hare takes 6 leaps, the grey-hound takes 7 leaps. 7 leaps of grey-hound is equal to 9 leaps of hare. In how many leaps will the grey-hound overtake the hare?
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let us assume that one leap of hare=1m
so we are given that
7 leaps of hound=9 leaps of hare
so 1leap of hound=9/7 leaps of hare
so 1leap of hound=9/7m
nd then lets assume that the hare makes one leap in 1 sec
time taken by hare to take 6 leaps =6secs
and 6sec=time taken by hound to make 7 leaps
so the hound makes 7/6leaps per sec
1 leap of hound=9/7m
so in 1 sec hound travels 7/6 x 9/7 m=3/2m
speed of hare is 1m/sec
and speed of hound is 1.5m/sec
and hare is 24 of her own leaps ahead =24m
so let the time taken by hound to capture the hare be t
so distance travelled by hound=distance traveled by hare+24m
1.5(t) = 1(t)+24
hound makes 7/6 leaps per sec so leaps made in 48 secs=7/6 x 48 =56