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Carissa15
 one year ago
I have a few questions with imaginary numbers. Please help.
Carissa15
 one year ago
I have a few questions with imaginary numbers. Please help.

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Carissa15
 one year ago
Best ResponseYou've already chosen the best response.11. Plot the following complex numbers in the plain and compute Re z, Im z, Z, IzI and arg z. i) z1=3i

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(z_1 = 3i = 0+3i\) so that goes \(0\) along Real axis and \(3\) along Imaginary axis : dw:1443006330020:dw

Carissa15
 one year ago
Best ResponseYou've already chosen the best response.1Not sure I understand how it got to 0+3i

Carissa15
 one year ago
Best ResponseYou've already chosen the best response.1It states to use z=x+iy

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(3i\) is same as \(0+3i\)

Carissa15
 one year ago
Best ResponseYou've already chosen the best response.1Ok, so you dont't have to "move" the z1 to the RHS?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3there is no "Real" component, so the complex number sticks vertically up

Carissa15
 one year ago
Best ResponseYou've already chosen the best response.1ok cool. Thanks. So the question is just asking for them to be plotted basically.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Yes and you need to compute the mentioned quantities too

Carissa15
 one year ago
Best ResponseYou've already chosen the best response.1What will they be? Re z is real z. Im z is imaginary z.

phi
 one year ago
Best ResponseYou've already chosen the best response.0Yes Re z is the real part. if you have z= 3i (or 0 + 3i if we want to explicitly show the real part), then Re 3i = 0 and Im 3i = 3 the magnitude  z  is the length of the line from the origin to the point use pythagoras z^2 = x^2 + y^2 where x and y are the real and imaginary components the angle is the inverse tangent of y/x

Carissa15
 one year ago
Best ResponseYou've already chosen the best response.1Thank you everyone for your help. :)
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