- anonymous

-(7y+6)(5y+4)
multiply and simplify
will medal

- katieb

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- MrNood

use the same as you were just shown
hint - be careful about the - sign outside first bracket....

- anonymous

thats correct
its on the outside of the bracket

- the_ocean_girl

i can walk you through it if you want

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## More answers

- anonymous

please i hate these

- anonymous

i have 3 i have to get right

- MrNood

Yes I know
I am asking YOU to use the same methodas oyu were just shown
BUT be careful about the - sign

- the_ocean_girl

okay so first you need to distribute the negative that's outside the first set of parentheses

- MrNood

I showed you the FOIL method
so what do you get when you multiply the FIRST terms from the 2 brackets together?

- anonymous

35y

- anonymous

would it be 35y^2

- MrNood

yes good
now the 2 O utrer terms?

- MrNood

"Outer"

- anonymous

24

- MrNood

Well - that is the two LAST terms - but its OK - we need that as well
so the OUTER terms are
7y and 4
the inner terms are
6 and 5y
so what do you get when you multiply THOSE pairs?

- anonymous

27y
30y

- anonymous

28y

- anonymous

sorry stupid computer

- MrNood

so the 2 brackets altogether are
35y^2 +27y + 30y + 24
we need to join the 2 terms with y in
AND THEN REMEMBER THE - sign
so first join the two y terms...

- MrNood

yes - 28 y is better sorry I mssed that

- MrNood

that is NOT a minus btw - just punctuation - sorry

- anonymous

35y^2-57y+28

- MrNood

it's 35y^2 +58 y + 28
OK
but we also have the minus sign outside ALL
so
-(35y^2 +58 y + 28 )
so now distribute the minus inside the bracket and you will have th eanswer
(AND you did it YOURSELF!) well done

- anonymous

thanks just a little confusing to me

- MrNood

you still need to do the minus into the bracket....

- anonymous

was just saying thanks doing it now

- anonymous

-35y^2-58y-28

- MrNood

excellent - good job
|dw:1443008538137:dw|
remember FOIL
you will get 4 terms, and you can always combine 2 of them...

- anonymous

thanks usually people just give answers and dont actually help

- MrNood

Well done for trying - many people just WANT the answers - but they don't learn from that

- anonymous

i have a different equation could u help explain that one

- MrNood

Put it in a new thread - I'll try - but haven't got much time...

- anonymous

its ok thanks

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