A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

AaronAndyson

  • one year ago

An object is 25 cm away from a convex len.The height of the image is twice the height of the object.Find it's focal length.

  • This Question is Closed
  1. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @Abhisar

  2. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Ok, I am gonna tell you a Super Formula for lens \(\sf \boxed{M=\frac{V}{U}=\frac{f}{f+u}=\frac{f-v}{f}=\frac{h_i}{h_o}}\)

  3. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    M= magnification, V=image distance u=object distance f=focal length \(\sf h_i~and~h_o\) are image and object height respectively.

  4. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Note: You need to follow the cartasian coordinate.

  5. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Never heard of that :/

  6. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Heard of what? Cartasian cordinate

  7. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Never heard of this Cartasian cordinate

  8. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Do you know about the sign convension?

  9. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    To be honest,I don't know a thing about Optics...

  10. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Ok, why don't you read this http://www.st-andrews.ac.uk/~bds2/optics/cartesian.html

  11. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Done.

  12. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    How do I solve this problem?

  13. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Use the formula m = f/f+u

  14. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    M is magnification. Because the height of the image is twice that of object so the magnification will be 2

  15. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You need to plug in the values with appropriate sign. that's it 2=f/f+ (-25)

  16. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -50 cm?

  17. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Re-check it should be in positive value

  18. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    50 cm?

  19. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes.

  20. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Thanks

  21. Abhisar
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Welcome c:

  22. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.