AaronAndyson
  • AaronAndyson
An object is 25 cm away from a convex len.The height of the image is twice the height of the object.Find it's focal length.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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AaronAndyson
  • AaronAndyson
@Abhisar
Abhisar
  • Abhisar
Ok, I am gonna tell you a Super Formula for lens \(\sf \boxed{M=\frac{V}{U}=\frac{f}{f+u}=\frac{f-v}{f}=\frac{h_i}{h_o}}\)
Abhisar
  • Abhisar
M= magnification, V=image distance u=object distance f=focal length \(\sf h_i~and~h_o\) are image and object height respectively.

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Abhisar
  • Abhisar
Note: You need to follow the cartasian coordinate.
AaronAndyson
  • AaronAndyson
Never heard of that :/
Abhisar
  • Abhisar
Heard of what? Cartasian cordinate
AaronAndyson
  • AaronAndyson
Never heard of this Cartasian cordinate
Abhisar
  • Abhisar
Do you know about the sign convension?
AaronAndyson
  • AaronAndyson
To be honest,I don't know a thing about Optics...
Abhisar
  • Abhisar
Ok, why don't you read this http://www.st-andrews.ac.uk/~bds2/optics/cartesian.html
AaronAndyson
  • AaronAndyson
Done.
AaronAndyson
  • AaronAndyson
How do I solve this problem?
Abhisar
  • Abhisar
Use the formula m = f/f+u
Abhisar
  • Abhisar
M is magnification. Because the height of the image is twice that of object so the magnification will be 2
Abhisar
  • Abhisar
You need to plug in the values with appropriate sign. that's it 2=f/f+ (-25)
AaronAndyson
  • AaronAndyson
-50 cm?
Abhisar
  • Abhisar
Re-check it should be in positive value
AaronAndyson
  • AaronAndyson
50 cm?
Abhisar
  • Abhisar
Yes.
AaronAndyson
  • AaronAndyson
Thanks
Abhisar
  • Abhisar
Welcome c:

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