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anonymous

  • one year ago

Can you help me get the number of atoms of H in 67.3 g N2H4?

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  1. anonymous
    • one year ago
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    I know there are 2.103 mol N2H4 and 1.27 molecules N2H4. |dw:1443012950126:dw| This is as far as i got, not sure if i'm doing in correctly though.

  2. anonymous
    • one year ago
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    @Zarkon @imqwerty @Rushwr can any of you help?

  3. imqwerty
    • one year ago
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    hallo :) i will halp

  4. imqwerty
    • one year ago
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    molar mass of N2H4 = 2(14)+4(1) =32 moles of N2H4 in 67.3gm sample =67.3/32 number of moles of H in 1 mole of N2H4 is 4 so number of moles of H in 67.3/32 moles of N2H4 =4(67.3/32)=67.3/8 number of atoms of H in 67.3/8 moles of H = 67.3/8 x Avagadro number =67.3 /8 x 6.023 x 10^(23) =5.06 x 10^24 atoms :)

  5. anonymous
    • one year ago
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    Awesome, Thank you! :)

  6. imqwerty
    • one year ago
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    np :) see this- http://prntscr.com/8jcveg

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