Please help me solve 1- 4(c-3) + 7 = 59 2-5g+4(5+3g) = 2 - g 3- k- 3k = 6k + 5 - 8k 4- -6a + 3 = -3(2a-1) Thanks

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Please help me solve 1- 4(c-3) + 7 = 59 2-5g+4(5+3g) = 2 - g 3- k- 3k = 6k + 5 - 8k 4- -6a + 3 = -3(2a-1) Thanks

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you need somebody to walk you through all 4 of them?
yes please
:)

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Other answers:

okay i'll take you through all of them so you understand
thank you
no problem. okay do you know the first step for #1?
divide. Maybe the 4 from each side?
distribute
distribute it to what's in the parentheses first
then we do the reverse order of operations
okay 4(c-3) = 4c - 12 + 7 = 59
now combine like terms
4c - 12 + 7
-12 and +7 are like terms combine them and then add that to 59
c = 54
you'll be left with 4c divide each side by 4 and that's how you get what c equals
c = 13.5
you should have gotten -5 when you combine like terms to get rid of the -5 you have to add 5
sorry i should have said that 1st
okay thats okay
it'll be 59+5 and then divide by 4
14.75?
59+5= 64 64/4=16
yay thank you
no problem! let's move on to #2
oky does #2 equal 37
how did you get to that answer
5g+4(5 + 3g) = 2 - g 5g + 4(8g) = 2-g 5g+32g = 2 - g 37g = 1g 37 = g
you can't combine 5 and 3g because 5 doesn't have a g that threw off your math you were supposed to begin with the distributive property again
oh okay thanks
5g + 20 + 12g = 2 - g
then do I combine the like terms?
hello?
sorry i was taking notes for a class
oh thats cool
yes you combine like terms now so 5g+3g
kay
**5g+12g
add?
yes add 5g and 12g
17g
okay so now you have 20+17g= 2-g
okay Do I combine 17g and g or just add regularly?
thanks Im sorry but I have to go
okay

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