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anonymous

  • one year ago

Find the x-intercepts of the parabola with vertex (-4,2)and y Intercept (0,-30) Wright answer if this form (x1,y1)(x2,y2).

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  1. anonymous
    • one year ago
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    i would also like to know how you did it

  2. Nnesha
    • one year ago
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    what's the vertex form of the parabola ?

  3. anonymous
    • one year ago
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    (y-k)=a(x-h)^2

  4. anonymous
    • one year ago
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    Bruh... okay here: http://openstudy.com/study#/updates/4fe123c7e4b06e92b8705343

  5. Nnesha
    • one year ago
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    hmm add k both sides so it would be \[\huge\rm y=a(x-h)^2+k\] vertex form where (h,k) is the vertex so substitute (h,k) for ( -4,2)

  6. anonymous
    • one year ago
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    so like (y-2)=a(x--4)^2

  7. Nnesha
    • one year ago
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    ye that would work so y-intercept is (0,-30) where x =0 and y =-30 so plugin \[\huge\rm -30-2=a(0-(-4))^2\] now solve for a

  8. anonymous
    • one year ago
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    so a =-2

  9. anonymous
    • one year ago
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    i appreciate your help btw

  10. Nnesha
    • one year ago
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    yes right now u can find x-intercept \[\huge \rm -30-2=-2(x-(-4))^2\] solve for x let me know if you don't know how to work it out

  11. anonymous
    • one year ago
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    x= 0,-8 Correct?

  12. Nnesha
    • one year ago
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    hmm plz show a little work...

  13. anonymous
    • one year ago
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    im using an online calculator because the only calculator we have broke im not quite shure how to do the steps myself without it.

  14. Nnesha
    • one year ago
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    hmm well do you want to know how to work it out without calculator ?

  15. anonymous
    • one year ago
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    couldent hurt mind if i get my notepad and pencil

  16. anonymous
    • one year ago
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    ok i got it

  17. Nnesha
    • one year ago
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    alright first we can multiply negative by (-4) -1 times -4 = 4 ( negative times negative = positive ) \[\huge \rm -30-2=-2(x+4))^2\] -30-2 = -32 \[\huge \rm -32=-2(x+4)^2\] now we should foil (x+4)^2 `(x+4)^2 `is same as (x+4)(x+4)

  18. Nnesha
    • one year ago
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    |dw:1443017713689:dw| now we should distribute 2nd parentheses by first and 2nd term of the 2nd parentheses (foil method ) so multiply left first term by top

  19. Nnesha
    • one year ago
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    x(x+4) =??

  20. anonymous
    • one year ago
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    x^2+4x ?

  21. anonymous
    • one year ago
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    or dise tge 4 not have an x

  22. Nnesha
    • one year ago
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    yes right |dw:1443017933992:dw| and then 4(x+4) = 4x +16 now combine like terms

  23. Nnesha
    • one year ago
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    x^2 +4x is correct :=)

  24. anonymous
    • one year ago
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    ohh ok Thanks!

  25. Nnesha
    • one year ago
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    |dw:1443018028522:dw|alright now combine like terms

  26. Nnesha
    • one year ago
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    do you know what are `like terms ` ?

  27. anonymous
    • one year ago
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    no :C

  28. anonymous
    • one year ago
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    i beilive they are x2 and 16 4x and 4x

  29. Nnesha
    • one year ago
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    hmm like terms that contains same variables

  30. Nnesha
    • one year ago
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    x^2 is same as 1x^2 so 16 and 1x^2 are the same ?

  31. Nnesha
    • one year ago
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    there is a variable with 1 but no variable with 16

  32. anonymous
    • one year ago
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    hmm so what dose that mean?

  33. Nnesha
    • one year ago
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    hmm like terms that contains the same variable so 1x^2 and 16 are like terms or not ?

  34. anonymous
    • one year ago
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    no coreect?

  35. Nnesha
    • one year ago
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    yes right so just combine 4x+4x just add the coefficient here is an example 2x+4x=(2+4)x =6x

  36. anonymous
    • one year ago
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    well 4x+4x is 8x

  37. Nnesha
    • one year ago
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    yes right \[-32=-2(x^2+8x+16)\] now distribute parentheses by -2

  38. Nnesha
    • one year ago
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    |dw:1443018609249:dw|

  39. anonymous
    • one year ago
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    umm ... i got 0,-8

  40. anonymous
    • one year ago
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    same as my answer from before so is it correct?

  41. Nnesha
    • one year ago
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    ohh well i was just asking abt -2(x^2+8x+16) but yes that is the answer if u use calculator not gonna force u to work by hand :D

  42. anonymous
    • one year ago
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    sorry iys touch im bad at numbers

  43. anonymous
    • one year ago
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    Sorry my its just im bad at numbers*

  44. anonymous
    • one year ago
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    so the asnwer to my origanal problem is 0,-8

  45. anonymous
    • one year ago
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    thanks

  46. Nnesha
    • one year ago
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    yw

  47. anonymous
    • one year ago
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    err 0,-8 was inccorect on my question

  48. anonymous
    • one year ago
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    yeet

  49. Nnesha
    • one year ago
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    are the solution you should write in two order pair (x1,y1)(x2,y2)

  50. Nnesha
    • one year ago
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    remember x-intercept when y =0 so when x=0 y=0 for 2nd order pair when x=-8 y=0

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