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- rock_mit182

find the distance between the
parallel planes:
a) 2x +y -2z =0 and 2x+y -2z =5

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- rock_mit182

find the distance between the
parallel planes:
a) 2x +y -2z =0 and 2x+y -2z =5

- katieb

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- happy_to_help

Is that how the question is written?

- rock_mit182

In Exercises 37 and 38, find the distance between the
parallel planes.
37. 2x + y - 2z = 0 and 2x + y - 2z = 5

- happy_to_help

This is the formula you have to use

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- rock_mit182

I guess i need that creepy formula: "In the case where the line £ is in IR2 and its equation has the general form
ax + by = c, the distance d(B, €) from B = (x0, y0) is given by the formula"

- happy_to_help

They dont give you a graph?

- rock_mit182

\[d(\beta,\iota) = \frac{ |a x_{0} + b y_{0}+ c| }{\sqrt{a ^{2}+b ^{2}} }\]

- rock_mit182

no, they don't give anything. But i guess it would be something like:|dw:1443017717632:dw|

- rock_mit182

@texaschic101 @inkyvoyd Could you give me a hand on this one..

- rock_mit182

- rock_mit182

In general, the distance d(B,

- welshfella

first you must find a point that lies on one of the planes
for the first equation x = y = z = 0 so there is the point (0,0,0) on that plane

- welshfella

so now you can use your formula

- rock_mit182

that's all ?

- rock_mit182

what if use a point of the other plane should i get the same answer ?

- welshfella

x0 y0 and z0 = 0 d = 5

- welshfella

yes I've never come across this formula before but i dont see why not
Its easy to use (0,0,0) though

- welshfella

the numerator will be 5
and plug in a = 2 , b = 1 and c = -2

- rock_mit182

ok it seems easy...
could you help me with this one:
Find the normal form of the equation of the plane that
passes through P = (O, - 2, 5 ) and is parallel to the
plane with general equation 6x - y + 2z = 3 .

- welshfella

I'd have to look all that stuff up I'm afraid but i haven't got the time at the moment.

- rock_mit182

ok fine, thanks anyway

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