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donnie1999

  • one year ago

can someone graph 5x-3y=15 please will medal

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  1. Fanduekisses
    • one year ago
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    Ok so first you need it in slope form: y= mx + b

  2. Fanduekisses
    • one year ago
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    m is the slope and b is the y-intercept, that is why that form is better for graphing. You plot the y-intercept then use slope to go either up or down and then to the left.

  3. Fanduekisses
    • one year ago
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    But get it in the y= mx + b form first, do this by getting y by itself so subtract 5x to both sides first.

  4. Fanduekisses
    • one year ago
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    you'll get -3y= -5x+ 15 You still don't have y by itself, there is a -3 in front. Let's get rid of it by doing the opposite, divide -3 to both sides...

  5. donnie1999
    • one year ago
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    the slope is 5/3

  6. Fanduekisses
    • one year ago
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    We get y=5/3y-5

  7. Fanduekisses
    • one year ago
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    Now you can graph, start at y= -5, (0,-5)

  8. Fanduekisses
    • one year ago
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    Use slope, which is 5/3, from -5 go up 5 and 3 to the right.

  9. donnie1999
    • one year ago
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    yah I did that so will the next point be 0,3 ? and do I have to shade anything?

  10. Fanduekisses
    • one year ago
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    Yes you got it but you don't need to shade anything, unless it were an inequality.

  11. donnie1999
    • one year ago
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    oh ok thanks :D

  12. Fanduekisses
    • one year ago
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    You should then end up with a line, just connect (0,-5) with (0,3)

  13. Fanduekisses
    • one year ago
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    You welcome! ^_^

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