anonymous
  • anonymous
Please help!!!! A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equation of this circle in standard form is
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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freckles
  • freckles
ok first state the standard form of a circle
anonymous
  • anonymous
(x-h)^2 + (y-k)^2=r^2
freckles
  • freckles
great

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freckles
  • freckles
now (h,k) is the center of the circle
freckles
  • freckles
you have these values h and k are given
freckles
  • freckles
your equation is so far: (x-5)^2+(y+4)^2=r^2 now you are also given a point (x,y) that is on the circle this will allow you to solve for r
freckles
  • freckles
That point being (-3,2) so replace x with -3 and y with 2 and solve for r
freckles
  • freckles
Please let know what you get for r.
anonymous
  • anonymous
9^2?
freckles
  • freckles
let me check
freckles
  • freckles
\[(-3-5)^2+(2+4)^2=r^2 \\ (-8)^2+(6)^2=r^2\] did you get this far?
anonymous
  • anonymous
yes
freckles
  • freckles
and so you winded up with 64+36=r^2 right?
anonymous
  • anonymous
yeah and i got confused
freckles
  • freckles
well 64+36 should be 100
freckles
  • freckles
you are really done because the standard form of a circle is (x-h)^2+(y-k)^2=r^2 where we needed values h,k , and r^2 we just found r^2 and we were given h and k
anonymous
  • anonymous
thank you soo much

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