## anonymous one year ago no $\pm \frac{ \frac{ 1 }{ 2 } }{ \frac{ \sqrt{3} }{ 2 } }=\pm \frac{ 1 }{ \sqrt{3} }=\pm \frac{ \sqrt{3} }{ 3 } = \pm \frac{ 1.732 }{ 3 }=?$

1. anonymous

$\sin x=\frac{ 1 }{ 2 }$ $\sin ^2x+\cos ^2x=1,\cos ^2x=\frac{ 3 }{ 4 }$ $\cos x=\pm \frac{ \sqrt{3} }{ 2 }$ $\tan x=\pm ?$

2. abb0t

When you have a square root, for example, you have $$\sf \sqrt{3}$$ what that actully is, is a exponent, so you have $$\sf 3^{\color{red}{{\frac{1}{2}}}}$$

3. abb0t

Oh, nevermind, ignore that. Memorize, SOH CAH TOA SOH = sine = opposite over hypotenuse TOA = tan = opposite over adjacent etc.,