anonymous
  • anonymous
All of the streets are depicted as either perpendicular or parallel lines. The equation of the lane passing through A and B is -7x + 3y = -21.5. What is the equation of the central street PQ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
any help?
anonymous
  • anonymous
-3x + 4y = 3 -1.5x − 3.5y = -31.5 2x + y = 20 -2.25x + y = -9.75
texaschic101
  • texaschic101
is PQ parallel or perpendicular to AB

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anonymous
  • anonymous
perpindicular
texaschic101
  • texaschic101
ok....perpendicular lines have negative reciprocal slopes. So first we find the slope of -7x + 3y = -21.5 3y = 7x - 21.5 -- divide by 3 y = 7/3x - 21.5/3 so the slope here is 7/3, but we need a negative reciprocal slope. To get that, we just flip the slope and change the sign. So the slope for the perpendicular line is -3/7 (see how I flipped the slope and changed the sign). -1.5x - 3.5y = -31.5 <--- this is your perpendicular equation -3.5y = 1.5x - 31.5 y = 1.5/-3.5x - 31.5/-3.5 y = - 3/7x + 9 <--- it has a negative reciprocal slope

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