Help with last problem..

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Help with last problem..

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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f(10)- f(0)/ 10-0 = (1.5 square root 10 +28.6) - (1.5 square root 0 +28.6)/ 10-0 Is that correct? Average rate of change was a few units ago. Need a refresher

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yes
Okay. Next I get rid of the parenthesis and distribute the - correct?
hmmm hold on
i don't bout this one but i think so i cant be too sure tho
= 1.5*sqrt(10)
?
  • phi
yes, your idea is correct f(10)- f(0)/ 10-0 or \[ (1.5 \sqrt{10} + 28.6 - 1.5 \sqrt{0} - 28.6)/10 \] notice the constant 28.6 subtracts off also the term 1.5 sqr(0) is just 1.5*0 =0 so it simplifies to \[ 0.15 \sqrt{10}\] now use a calculator or type 0.15*sqrt(10)= into google and round the answer to the nearest 10th
It says .47
How did you get 0.15.. Shouldn't it stay as 1.5?
Final answer .5
  • phi
How did you get 0.15.. Shouldn't it stay as 1.5? the "bottom" is 10 remember? ( f(10) - f(0) )/ (10 -0) the top simplifies to \( 1.5\sqrt{10} \) but we divide that by 10
You put 0.15
I thought it was 1.5. But above you put 0.15
  • phi
yes \[ \frac{1.5\sqrt{10}}{10}= 0.15 \sqrt{10} \]
Ohh okay

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