A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Help with last problem..
anonymous
 one year ago
Help with last problem..

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(10) f(0)/ 100 = (1.5 square root 10 +28.6)  (1.5 square root 0 +28.6)/ 100 Is that correct? Average rate of change was a few units ago. Need a refresher

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. Next I get rid of the parenthesis and distribute the  correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i don't bout this one but i think so i cant be too sure tho

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, your idea is correct f(10) f(0)/ 100 or \[ (1.5 \sqrt{10} + 28.6  1.5 \sqrt{0}  28.6)/10 \] notice the constant 28.6 subtracts off also the term 1.5 sqr(0) is just 1.5*0 =0 so it simplifies to \[ 0.15 \sqrt{10}\] now use a calculator or type 0.15*sqrt(10)= into google and round the answer to the nearest 10th

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did you get 0.15.. Shouldn't it stay as 1.5?

phi
 one year ago
Best ResponseYou've already chosen the best response.1How did you get 0.15.. Shouldn't it stay as 1.5? the "bottom" is 10 remember? ( f(10)  f(0) )/ (10 0) the top simplifies to \( 1.5\sqrt{10} \) but we divide that by 10

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I thought it was 1.5. But above you put 0.15

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes \[ \frac{1.5\sqrt{10}}{10}= 0.15 \sqrt{10} \]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.