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XxMuslimxX

  • one year ago

Find the average for the following numbers: A) 12 11 1/2 11 2/8 B) 11 7 9 C) 12 13 10

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  1. calculusxy
    • one year ago
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    finding the average is basically adding up all of the numbers and then dividing it by how many numbers there were on the data set. e.g. find the average of 10, 20, 30 \[\large \frac{ 10 + 20 + 30 }{ 3 } =\frac{ 60 }{ 3 } = 20\] so 20 is the average from this example data set

  2. XxMuslimxX
    • one year ago
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    I know. But A is confusing for me...

  3. calculusxy
    • one year ago
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    \[\large \frac{ 12 + 11 \frac{ 4 }{ 8 } 11 \frac{ 2 }{ 8 } }{ 3 }\]

  4. calculusxy
    • one year ago
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    notice how i changed 11 1/2 to 11 4/8

  5. XxMuslimxX
    • one year ago
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    34 6/8

  6. calculusxy
    • one year ago
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    no 34 3/4

  7. calculusxy
    • one year ago
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    \[\frac{ 6 \div 2 }{ 8 \div 2 } = \frac{ 3 }{ 4 }\]

  8. XxMuslimxX
    • one year ago
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    Oh yeah. My bad. I got carried away.

  9. XxMuslimxX
    • one year ago
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    The next step would be dividing that by 3.

  10. calculusxy
    • one year ago
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    yes

  11. XxMuslimxX
    • one year ago
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    That's where I got stuck...

  12. XxMuslimxX
    • one year ago
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    |dw:1443036449032:dw|

  13. XxMuslimxX
    • one year ago
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    @calculusxy

  14. anonymous
    • one year ago
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    Tip: \(\huge \frac{ 3 }{ 4 }\) can also be written as \(\huge 0.75\).

  15. anonymous
    • one year ago
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    |dw:1443036672177:dw|

  16. XxMuslimxX
    • one year ago
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    Yeah...I know, but I do not see how that can help?

  17. anonymous
    • one year ago
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    Oh really? You don't know how to do this? Okay... |dw:1443036762728:dw|

  18. XxMuslimxX
    • one year ago
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    Humiliating me doesn't help either.

  19. XxMuslimxX
    • one year ago
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    OK. I did some calculations and got 12 1/2....can someone check if it correct for me...?

  20. anonymous
    • one year ago
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    No one's humiliating you. :)

  21. XxMuslimxX
    • one year ago
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    "Oh really? You don't know how to do this?"

  22. XxMuslimxX
    • one year ago
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    For C I got 11 67⁄100....is that correct?

  23. anonymous
    • one year ago
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    Oh, was I being rude? Lol I didn't know that. :D Btw, your answer in A is not correct.

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