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Pulsified333

  • one year ago

Someone help I will give medal Question involving the rolling of two fair dice. What is the probability of one of the dice showing 3 or the sum being at least 8?

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  1. anonymous
    • one year ago
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    Well do you know how to compute probability?

  2. Pulsified333
    • one year ago
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    yes I do, I thought the answer was 16/36 but it was wrong

  3. anonymous
    • one year ago
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    So the probability of rolling 3 is equal on /both/ of them so we just leave that probability as 1/6th, not 1/12th. Does that help?

  4. anonymous
    • one year ago
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    Huh? On a fair dice there's a 1 in six chance of rolling a 3.

  5. Pulsified333
    • one year ago
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    yes but can't you roll a 3 on lets say die 1 or die 2?

  6. anonymous
    • one year ago
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    Yes, but that's 2/12 chance, which simplifies down to 1/6.

  7. Pulsified333
    • one year ago
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    oh

  8. anonymous
    • one year ago
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    Actually, 16/36 can be simplified. Maybe the answer needs to be simplified. What format is the test?

  9. Pulsified333
    • one year ago
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    it simplifies it for you

  10. anonymous
    • one year ago
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    Oh. well then.

  11. anonymous
    • one year ago
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    So we've got 1/6th. Then we need to work out the chance of rolling a sum of of over eight and add it to 1/6th.

  12. Pulsified333
    • one year ago
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    would it be over 36?

  13. anonymous
    • one year ago
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    The denominator?

  14. Pulsified333
    • one year ago
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    yes

  15. anonymous
    • one year ago
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    IDK XD I'll work it out.

  16. anonymous
    • one year ago
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    So how many combinations are there that equal above 8?

  17. Pulsified333
    • one year ago
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    5

  18. anonymous
    • one year ago
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    So there is a 5/36 (yeah, it is 36) chance of getting +8. So find a common denominator between 1/6th and 5/36ths and add them together.

  19. Pulsified333
    • one year ago
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    i made a mistake

  20. Pulsified333
    • one year ago
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    its the sum of at least 8

  21. Pulsified333
    • one year ago
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    which equals 15/36

  22. anonymous
    • one year ago
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    Ok. So still, multiply 'till you've got a common denominator + add them together.

  23. Pulsified333
    • one year ago
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    quick question

  24. anonymous
    • one year ago
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    Yeah?

  25. Pulsified333
    • one year ago
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    wouldn't the probability of getting a 3 on one die be 10/36

  26. anonymous
    • one year ago
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    I think the probability of 1 showing a 3 is 11/36. http://www.sms.rcs.k12.tn.us/TEACHERS/flaniganj/TEST/chapter_9_files/i0100000.jpg

  27. anonymous
    • one year ago
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    Well 36/6 = 6 so it's 6/36

  28. Pulsified333
    • one year ago
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    where is the 6 coming from?

  29. Pulsified333
    • one year ago
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    would the answer be 25/36

  30. anonymous
    • one year ago
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    You can get a 3 six different way on the first die, and 6 different ways on the second die. But two of those is (3, 3) so you subtract 1 to get 11/36 ways. 11/36 + 15/13 = 26/36

  31. anonymous
    • one year ago
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    * 11/36 + 15/36 = 26/36

  32. Pulsified333
    • one year ago
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    oh i see

  33. Pulsified333
    • one year ago
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    the answer is still wrong

  34. anonymous
    • one year ago
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    Well you're multiplying both sides of the fraction to give it 36 as a denominator, and you need to times 6 by 6 to get to 36, so so you also multiply 1 by six to get from 1/6 to 6/36, which you can add to 15/36.

  35. anonymous
    • one year ago
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    Which by my admittedly thirteen-year-old brain is 21/36.

  36. anonymous
    • one year ago
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    did you try the 25/36 you came up with? I'm guessing they want you to exclude the double roll.

  37. Pulsified333
    • one year ago
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    yeah probably because it says one 3 not 2

  38. anonymous
    • one year ago
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    was that it?

  39. Pulsified333
    • one year ago
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    i didn't try it yet. I only have 2 attempts left

  40. Pulsified333
    • one year ago
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    do you think 25/36 would be the right answer if its not including the double roll

  41. anonymous
    • one year ago
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    yeah, not including it, it's 25/36. including it, it's 26/36 or 13/18.

  42. Pulsified333
    • one year ago
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    no its not it either

  43. Pulsified333
    • one year ago
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    ;(

  44. anonymous
    • one year ago
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    red = one 3 blue = sum at least 8|dw:1443039212787:dw|

  45. anonymous
    • one year ago
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    there are 4 double counts. so they have to be subtracted. 10/36 + 15/36 - 4/36 = 21/36

  46. anonymous
    • one year ago
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    I think

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