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monkey*
 one year ago
Xy+z=5
2xyz=6
3x+3y2z=5
Solve algebraically.
monkey*
 one year ago
Xy+z=5 2xyz=6 3x+3y2z=5 Solve algebraically.

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texaschic101
 one year ago
Best ResponseYou've already chosen the best response.1ohhhh...these are a pain in the butt. Very time consuming. here we go... x  y + z = 5  multiply by 1 2x  y  z = 6  x + y  z = 5 (result of multiplying by 1) 2x  y  z = 6 add 3x  2z =  11 x  y + z = 5  multiply by 3 3x + 3y  2z = 5  3x  3y + 3z = 15 (result of multiplying by 3) 3x + 3y  2z = 5 add 6x + z = 10 3x  2z = 11 6x + z = 10  multiply by 2  3x  2z = 11 12x + 2z = 20 (result of multiplying by 2) add 9x = 9 x = 1 6x + z = 10 6(1) + z = 10 6 + z = 10 z = 10  6 z = 4 x  y + z = 5 1  y + 4 = 5 5  y = 5 y = 0 y = 0 check... 2x  y  z = 6 2(1)  0  4 = 6 2  4 = 6 6 = 6 (correct) so x = 1, y = 0, and z = 4

texaschic101
 one year ago
Best ResponseYou've already chosen the best response.1It would probably be easier to use matrices....I am just not too good with those

monkey*
 one year ago
Best ResponseYou've already chosen the best response.0I was extremely confused, thank you so much for clearing it up for me. This is a huge help. Thank you so much! I'm not too great at matrices, either.
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