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haleyelizabeth2017
 one year ago
Find the minimum value of the function for the polygonal convex set determined by the given system of inequalities. Please no direct answers.
haleyelizabeth2017
 one year ago
Find the minimum value of the function for the polygonal convex set determined by the given system of inequalities. Please no direct answers.

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haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0\(2x+2y\ge 16\) \(2x+6y\le 24\) \(4x+4y\ge 8\) \(f(x,y)=5x+4y\)

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0@phi think you can help?

aaronq
 one year ago
Best ResponseYou've already chosen the best response.0I dont really remember how to do this and i dont want to give you a crappy answer, buti think this video may be helpful https://www.youtube.com/watch?v=RPuhkQ0vGK0

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Perhaps...that's the next lesson I have....

phi
 one year ago
Best ResponseYou've already chosen the best response.1How far did you get? I think you plot the relations, and find the intersection points then at each intersection point, evaluate the function f(x,y)

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Ah...I'm still watching video lol

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Graphing inequalities now...

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0The next step the dude shows is confusing..."cover up the x"?

phi
 one year ago
Best ResponseYou've already chosen the best response.1I used geogebra to plot them

phi
 one year ago
Best ResponseYou've already chosen the best response.1that is the hard part, finding the intersection points once you have them, you have (x,y) pairs that you "evaluate" using f(x,y) = 5x+4y

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Okay, the inequalities intersect at (3,5), (9,7), (5,3).

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Do I plug them into the equation?

phi
 one year ago
Best ResponseYou've already chosen the best response.1at every point on the graph f(x,y) has a value. But the max or min values will always occur at one of the vertexes (intersection points of the boundaries) so we test each vertex. One will be the min and that is the pair we pick

phi
 one year ago
Best ResponseYou've already chosen the best response.1Did you do the other 2 pairs?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Minimum is at (3,5) :)

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Yes! f(9,7)=73 and f(5,3)=37 :D

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0That seems easier than I thought it would be...

phi
 one year ago
Best ResponseYou've already chosen the best response.1what did you get for (5,3) ?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Mind helping me with a couple more?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0It's probably easier than I think it will be...brain isn't working today lol

phi
 one year ago
Best ResponseYou've already chosen the best response.1no, my brain was not working and I confused 5,3 and 3,5 but yes, the answer is at 3,5 they want Find the minimum value of the function , so 35 is the answer

phi
 one year ago
Best ResponseYou've already chosen the best response.1The painful part of these problems is plotting the relations, and finding the intersection points. If you can use something like geogebra or other such tools, then the problems are not too hard.

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Lol the next ones I have to plot two inequalities and state which numbered region or regions belong to the solution...

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0After you showed me what to do, that one was pretty easy :)

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.0Thank you, by the way :)
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