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anonymous

  • one year ago

What is the average vector acceleration of a car that changes its velocity from 30km/h south to 40km/h east over a time of 5.0s?

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  1. johnweldon1993
    • one year ago
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    Hmm, kinda worded weird However..we know \(\Large a = \frac{\Delta v}{t}\) Since the velocity is changing directions as well...it wont simplify COMPLETELY! but that's okay \[\large a = \frac{40i - 30j }{5.0}\] I hope you know that notation: "i" meaning in the x-direction and "j" meaning in the y-direction So that acceleration vector would be \[\large \vec{a} = 8i - 6j\]

  2. johnweldon1993
    • one year ago
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    Which kinda makes sense if you think about it...the motion looks like |dw:1443043644332:dw|

  3. johnweldon1993
    • one year ago
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    If we look on a coordinate plane |dw:1443043692012:dw|

  4. johnweldon1993
    • one year ago
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    So the resulting vector would be down down (so -j) and going right (so +i)

  5. anonymous
    • one year ago
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    shouldn't the j portion be negative and then you get 40--30

  6. anonymous
    • one year ago
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    And how would i give a numerical answer with an angle and km/h/s for velocity?

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