## cutiecomittee123 one year ago tan(25pi/2)= How do i solve for this? The options are: 0 1 -1 undefined

1. javalos01

hello do you need help

2. cutiecomittee123

yes. but i already found out the answer to this question here is another that i need help with if you are willing to help that would be awesome "The statement tantheta=-12/5 and csctheta==13/12 and the terminal point determined by theta is in quadrant 3....... a.cannot be true because 12^2+5^2 does not equal 1" b.cannot be true because if tantheta=-12/5 then csctheat=+-13/5" c.cannot be true because tantheta must be less than one" d.cannot be true because tantheta is greater than zero in quadrant 3" Which one of these fits the best and why?

3. cutiecomittee123

@javalos01

4. cutiecomittee123

I know that if it is in quadrant 3 then sintheta is negative and costheta is positive.

5. javalos01

ok what do u need

6. javalos01

correct go on

7. javalos01

if all of them are wrong there has to be a correct one

8. javalos01

which one do you for sure think it is

9. cutiecomittee123

i think that a is the correct one because when you are trying to solve for a trigonometric eqtuation and you have two sides you always set it equal to one. and if 12^2+5^2 arent equal to 1 it cannot be true

10. javalos01

ok i gtg and i think ur correct

11. cutiecomittee123

well thanks

12. anonymous

$\tan \frac{ 25 \pi }{ 2 }=\tan \left( 6\times 2 \pi+\frac{ \pi }{ 2 } \right)=\tan \frac{ \pi }{ 2 }=in finity$

13. anonymous

infinity means undefined.

14. cutiecomittee123

oh i see thanks for that!

15. cutiecomittee123

can you help with my other question. did i chose the right answer?

16. anonymous

sure ,if possible.

17. cutiecomittee123

alright its on here already and that guy tried to help me but iw as wondering if you can double check it for me its the question above ^^^

18. anonymous

ok

19. anonymous

20. anonymous

here csc theta is positive, tan theta is negative so theta lies in 2nd quadrant.

21. anonymous

d is correct.

22. anonymous

d says statement is wrong because tan theta >0 in quadrant 3.

23. cutiecomittee123

but how would tantheta be postitive when its y/x and y is negative -y/x= a negative outcome

24. cutiecomittee123

@surjithayer

25. anonymous

|dw:1443059466366:dw|

26. cutiecomittee123

oh yeah. okay gotcha! and that cannot work so it must be in the second quadrant because tantheta is greater than 0 in quadrant 3 and in the statment it says that tan is negative

27. cutiecomittee123

awesome thanks

28. anonymous

yw