cutiecomittee123
  • cutiecomittee123
tan(25pi/2)= How do i solve for this? The options are: 0 1 -1 undefined
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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javalos01
  • javalos01
hello do you need help
cutiecomittee123
  • cutiecomittee123
yes. but i already found out the answer to this question here is another that i need help with if you are willing to help that would be awesome "The statement tantheta=-12/5 and csctheta==13/12 and the terminal point determined by theta is in quadrant 3....... a.cannot be true because 12^2+5^2 does not equal 1" b.cannot be true because if tantheta=-12/5 then csctheat=+-13/5" c.cannot be true because tantheta must be less than one" d.cannot be true because tantheta is greater than zero in quadrant 3" Which one of these fits the best and why?
cutiecomittee123
  • cutiecomittee123
@javalos01

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cutiecomittee123
  • cutiecomittee123
I know that if it is in quadrant 3 then sintheta is negative and costheta is positive.
javalos01
  • javalos01
ok what do u need
javalos01
  • javalos01
correct go on
javalos01
  • javalos01
if all of them are wrong there has to be a correct one
javalos01
  • javalos01
which one do you for sure think it is
cutiecomittee123
  • cutiecomittee123
i think that a is the correct one because when you are trying to solve for a trigonometric eqtuation and you have two sides you always set it equal to one. and if 12^2+5^2 arent equal to 1 it cannot be true
javalos01
  • javalos01
ok i gtg and i think ur correct
cutiecomittee123
  • cutiecomittee123
well thanks
anonymous
  • anonymous
\[\tan \frac{ 25 \pi }{ 2 }=\tan \left( 6\times 2 \pi+\frac{ \pi }{ 2 } \right)=\tan \frac{ \pi }{ 2 }=in finity\]
anonymous
  • anonymous
infinity means undefined.
cutiecomittee123
  • cutiecomittee123
oh i see thanks for that!
cutiecomittee123
  • cutiecomittee123
can you help with my other question. did i chose the right answer?
anonymous
  • anonymous
sure ,if possible.
cutiecomittee123
  • cutiecomittee123
alright its on here already and that guy tried to help me but iw as wondering if you can double check it for me its the question above ^^^
anonymous
  • anonymous
ok
anonymous
  • anonymous
your statement is wrong tan theta is positive in quadrant 3
anonymous
  • anonymous
here csc theta is positive, tan theta is negative so theta lies in 2nd quadrant.
anonymous
  • anonymous
d is correct.
anonymous
  • anonymous
d says statement is wrong because tan theta >0 in quadrant 3.
cutiecomittee123
  • cutiecomittee123
but how would tantheta be postitive when its y/x and y is negative -y/x= a negative outcome
cutiecomittee123
  • cutiecomittee123
@surjithayer
anonymous
  • anonymous
|dw:1443059466366:dw|
cutiecomittee123
  • cutiecomittee123
oh yeah. okay gotcha! and that cannot work so it must be in the second quadrant because tantheta is greater than 0 in quadrant 3 and in the statment it says that tan is negative
cutiecomittee123
  • cutiecomittee123
awesome thanks
anonymous
  • anonymous
yw

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