If 0^2/3 equals 0, why is 0^-2/3 an undefined?

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If 0^2/3 equals 0, why is 0^-2/3 an undefined?

Algebra
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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there is a negative sign so you should flip the fraction to convert negative to positive exponent \[\huge\rm x^{-m}=\frac{ 1 }{ x^{m}}\] and use the fact that u can't divide by 0
But why is it undefined?
you can't divide by if the denominator is 0 then answer would be undefined \[\huge\rm \frac{ 1 }{ 0 }=undefined \]\[\frac{ 0 }{ 1 }=0\]

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Oh. Okay. Thanks. ^-^
np :=)

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