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muscrat123

  • one year ago

Molly's Custom Kitchen Supplies sells homemade forks and spoons. It costs the store $1.70 to buy the supplies to make a fork and $1.30 to buy the supplies to make a spoon. The store sells forks for $5.60 and spoons for 5.40. Last April Molly's Custom Kitchen Supplies spent $37.90 on materials for forks and spoons. They sold the finished products for a total of $147.20. How many forks and how many spoons did they make last April?

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  1. muscrat123
    • one year ago
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    @Hero

  2. Compassionate
    • one year ago
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    This is asking for a system of equations, am I right? Are you familiar with system of equations?

  3. muscrat123
    • one year ago
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    yea and yea. i know how to do this stuff, its just this one problem

  4. Compassionate
    • one year ago
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    "Molly's Custom Kitchen Supplies sells homemade forks and spoons. It costs the store $1.70 to buy the supplies to make a fork and $1.30 to buy the supplies to make a spoon. The store sells forks for $5.60 and spoons for 5.40. Last April Molly's Custom Kitchen Supplies spent $37.90 on materials for forks and spoons. They sold the finished products for a total of $147.20. How many forks and how many spoons did they make last April?" So it costs the store: 1.70 and 1.30 f = 1.70 s = 1.30 f + s = 37.90 1.70f + 1.30s = 37.90 In theory, if you solve the system, you can plug each term in and found out how many forks and spoons they bought, then divide it by the sell price

  5. muscrat123
    • one year ago
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    i have that

  6. Compassionate
    • one year ago
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    Would you like to clarify which part you're having trouble with so I may be more direct?

  7. muscrat123
    • one year ago
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    well i have this: 1.70f + 1.30s = 37.90 5.60f + 5.40s = 147.20 i dont know where to go from there

  8. muscrat123
    • one year ago
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    my teacher said that part was right

  9. Hero
    • one year ago
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    I agree with @muscrat123 setup

  10. Compassionate
    • one year ago
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    Let's see.... Cost 1.70f + 1.30s = 37.90 Revenue 5.60x + 5.40y = 147.20 So now we have two equations, and we can solve either by either a system of elimination or substitution. It looks like elimination would be easier her, as substitution often requires a variable to already be found 1.70f + 1.30s = 37.90 5.60 + 5.40 = 147.20 If I can multiply our first equation by 5.6 and the second by 1.7, I can cancel some variables 9.52f + 7.28s = 212.24 9.52f+ 9.18s = 250.24 Now I can subtract the first equation from the second. Now that I've set it up, do you think you can show me some work?

  11. muscrat123
    • one year ago
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    sure give me like 10 mins is that ok? i have to do something else first.

  12. Compassionate
    • one year ago
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    I'll here. Just remember, time waits for no one.

  13. muscrat123
    • one year ago
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    what does i'll here mean?

  14. Compassionate
    • one year ago
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    It means my keyboard is messed up. I'll be here.

  15. muscrat123
    • one year ago
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    oh ok

  16. muscrat123
    • one year ago
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    i got 7 forks and 20 spoons f = 7 s = 20

  17. muscrat123
    • one year ago
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    thanks guys

  18. Hero
    • one year ago
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    Great job @musicrat and @Compassionate

  19. Compassionate
    • one year ago
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    That's correct @muscrat123 ! Thanks, @Hero

  20. muscrat123
    • one year ago
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    thanks i cant believe i missed that

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