anonymous
  • anonymous
Hi Everyone. A ball is connected to a hope that is puled horizontally with the force 20N through a pulley. In addition, the gravitational force 10N from the Earth acts on the ball. What is the magnitude and direction of the resultant force acted upon the ball
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1443411409966:dw|
BAdhi
  • BAdhi
|dw:1443412201434:dw| the directions of the forces mentioned on the rope are the forces acted on the man, pulley, pulley and the object if we go along the rope from man to the object
BAdhi
  • BAdhi
all those forces will have a value of 20N

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so there is T force up the rope from the ball, mg down from the ball toward the ground, all equaling 20N. The magnitude is the square root of 20 squared + 10 squared?
BAdhi
  • BAdhi
isnt mg = 10N?
BAdhi
  • BAdhi
\(F_r = \sqrt{F_a^2+F_b^2}\) is only when \(F_a\) and \(F_b\) are perpendicular the original equation is, \(F_r = \sqrt{F_a^2+F_b^2-2F_aF_b \cos\theta}\) But you dont have to consider those equations anyway since these forces act on the same line. so you can jst add or subtract

Looking for something else?

Not the answer you are looking for? Search for more explanations.