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anonymous

  • one year ago

Hi Everyone. A ball is connected to a hope that is puled horizontally with the force 20N through a pulley. In addition, the gravitational force 10N from the Earth acts on the ball. What is the magnitude and direction of the resultant force acted upon the ball

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  1. anonymous
    • one year ago
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    |dw:1443411409966:dw|

  2. BAdhi
    • one year ago
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    |dw:1443412201434:dw| the directions of the forces mentioned on the rope are the forces acted on the man, pulley, pulley and the object if we go along the rope from man to the object

  3. BAdhi
    • one year ago
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    all those forces will have a value of 20N

  4. anonymous
    • one year ago
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    so there is T force up the rope from the ball, mg down from the ball toward the ground, all equaling 20N. The magnitude is the square root of 20 squared + 10 squared?

  5. BAdhi
    • one year ago
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    isnt mg = 10N?

  6. BAdhi
    • one year ago
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    \(F_r = \sqrt{F_a^2+F_b^2}\) is only when \(F_a\) and \(F_b\) are perpendicular the original equation is, \(F_r = \sqrt{F_a^2+F_b^2-2F_aF_b \cos\theta}\) But you dont have to consider those equations anyway since these forces act on the same line. so you can jst add or subtract

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