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anonymous

  • one year ago

Find the average value of the function over the given interval. (Round your answer to four decimal places.) f(x) = 4 − x2, [−2, 2]

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  1. Compassionate
    • one year ago
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    @Hero , @Satellite7 , @kropot72

  2. zzr0ck3r
    • one year ago
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    The average value of \(f\) on the interval \([a,b]\) is given by \[\frac{1}{b-a}\int_a^bf(x)dx\]

  3. zzr0ck3r
    • one year ago
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    What is the integral of the function?

  4. zzr0ck3r
    • one year ago
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    without the constant...

  5. anonymous
    • one year ago
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    yeah I've gotten the same answer like a million times but it says its wrong the integral is (-2,2)

  6. anonymous
    • one year ago
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    why did you switch 4x & \[x ^{3}\]

  7. zzr0ck3r
    • one year ago
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    \[\dfrac{1}{2-(-2)}[4x-\frac{1}{3}x^3]_{-2}^2\]

  8. zzr0ck3r
    • one year ago
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    sorry brain old

  9. anonymous
    • one year ago
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    okay so yeah i did that.. will you calculate it for me? see what you get?

  10. anonymous
    • one year ago
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    I got 2.6665

  11. zzr0ck3r
    • one year ago
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    http://www.wolframalpha.com/input/?i=%281%2F4%29%5Cint_%7B-2%7D%5E2%284-x%5E2%29dx

  12. anonymous
    • one year ago
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    OH MY WORD hahaha there's a part b though too

  13. anonymous
    • one year ago
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    Just kidding, I got it :)

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spraguer (Moderator)
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