A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

cutiecomittee123

  • one year ago

If sintheta=2/3 which of the following are possible? sectheta= -3/2 and tantheta= 2/root5 costheta= -root5/3 and tantheta= 2/root5 costheta= root5/3 and tantheta= 2/root5 sectheta= 3/root5 and tantheta= 2/root5

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443065980821:dw|

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    First find the missing side. We know that sin\(\theta\)=\(\frac{2}{3}\), so the opposite side is \(2\), and the hypotenuse is \(3\). Now we need to find the adjacent. Use the Pythagorean theorem. \(c^2=a^2+b^2\) \(3^2=2^2+b^2\) \(b^2=9-4\) \(b=\sqrt{5}\) So the adjacent side is \(\sqrt{5}\).

  3. cutiecomittee123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay im with it so far

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So now we know the three sides: opposite: 2 adjacent: \(\sqrt {5}\) hypotenuse: 3 ---- We know that \(\huge cos\theta\)=\(\huge \frac {adjacent}{hypotenuse}\) so \(\huge cos\theta\)=\(\huge \frac {\sqrt{5} }{3}\)

  5. cutiecomittee123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Now that we have the sides which are 2,3, and -root5 we know that sin=-3/root5 cos=2/5 tan=3/2 sec=-root5/2 csc= -root5/3 and cot= 2/3

  6. cutiecomittee123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i didnt mean negative root 5 just root 5

  7. cutiecomittee123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but i also see that i messed up

  8. cutiecomittee123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Oops okay i had them in the wrong order then

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    And \(\tan\theta =\huge \frac {oposite}{adjacent}\), so \(\tan\theta =\huge \frac {2}{\sqrt{5}}\) or \(\huge \frac {2\sqrt{5}} {5}\) .

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    opposite*

  11. cutiecomittee123
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So that means that the last two in my question are the best two options

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes! :)

  13. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.