cutiecomittee123
  • cutiecomittee123
If sintheta=2/3 which of the following are possible? sectheta= -3/2 and tantheta= 2/root5 costheta= -root5/3 and tantheta= 2/root5 costheta= root5/3 and tantheta= 2/root5 sectheta= 3/root5 and tantheta= 2/root5
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1443065980821:dw|
anonymous
  • anonymous
First find the missing side. We know that sin\(\theta\)=\(\frac{2}{3}\), so the opposite side is \(2\), and the hypotenuse is \(3\). Now we need to find the adjacent. Use the Pythagorean theorem. \(c^2=a^2+b^2\) \(3^2=2^2+b^2\) \(b^2=9-4\) \(b=\sqrt{5}\) So the adjacent side is \(\sqrt{5}\).
cutiecomittee123
  • cutiecomittee123
okay im with it so far

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So now we know the three sides: opposite: 2 adjacent: \(\sqrt {5}\) hypotenuse: 3 ---- We know that \(\huge cos\theta\)=\(\huge \frac {adjacent}{hypotenuse}\) so \(\huge cos\theta\)=\(\huge \frac {\sqrt{5} }{3}\)
cutiecomittee123
  • cutiecomittee123
Now that we have the sides which are 2,3, and -root5 we know that sin=-3/root5 cos=2/5 tan=3/2 sec=-root5/2 csc= -root5/3 and cot= 2/3
cutiecomittee123
  • cutiecomittee123
i didnt mean negative root 5 just root 5
cutiecomittee123
  • cutiecomittee123
but i also see that i messed up
cutiecomittee123
  • cutiecomittee123
Oops okay i had them in the wrong order then
anonymous
  • anonymous
And \(\tan\theta =\huge \frac {oposite}{adjacent}\), so \(\tan\theta =\huge \frac {2}{\sqrt{5}}\) or \(\huge \frac {2\sqrt{5}} {5}\) .
anonymous
  • anonymous
opposite*
cutiecomittee123
  • cutiecomittee123
So that means that the last two in my question are the best two options
anonymous
  • anonymous
Yes! :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.