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cutiecomittee123
 one year ago
If sintheta=2/3 which of the following are possible?
sectheta= 3/2 and tantheta= 2/root5
costheta= root5/3 and tantheta= 2/root5
costheta= root5/3 and tantheta= 2/root5
sectheta= 3/root5 and tantheta= 2/root5
cutiecomittee123
 one year ago
If sintheta=2/3 which of the following are possible? sectheta= 3/2 and tantheta= 2/root5 costheta= root5/3 and tantheta= 2/root5 costheta= root5/3 and tantheta= 2/root5 sectheta= 3/root5 and tantheta= 2/root5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443065980821:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First find the missing side. We know that sin\(\theta\)=\(\frac{2}{3}\), so the opposite side is \(2\), and the hypotenuse is \(3\). Now we need to find the adjacent. Use the Pythagorean theorem. \(c^2=a^2+b^2\) \(3^2=2^2+b^2\) \(b^2=94\) \(b=\sqrt{5}\) So the adjacent side is \(\sqrt{5}\).

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0okay im with it so far

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now we know the three sides: opposite: 2 adjacent: \(\sqrt {5}\) hypotenuse: 3  We know that \(\huge cos\theta\)=\(\huge \frac {adjacent}{hypotenuse}\) so \(\huge cos\theta\)=\(\huge \frac {\sqrt{5} }{3}\)

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0Now that we have the sides which are 2,3, and root5 we know that sin=3/root5 cos=2/5 tan=3/2 sec=root5/2 csc= root5/3 and cot= 2/3

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0i didnt mean negative root 5 just root 5

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0but i also see that i messed up

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0Oops okay i had them in the wrong order then

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And \(\tan\theta =\huge \frac {oposite}{adjacent}\), so \(\tan\theta =\huge \frac {2}{\sqrt{5}}\) or \(\huge \frac {2\sqrt{5}} {5}\) .

cutiecomittee123
 one year ago
Best ResponseYou've already chosen the best response.0So that means that the last two in my question are the best two options
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